python JSON只获取第一级的键
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/15789059/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
python JSON only get keys in first level
提问by TeNNoX
I have a very long and complicated json object but I only want to get the items/keys in the first level!
我有一个非常长且复杂的 json 对象，但我只想获取第一级中的项目/键！
Example:
例子：
{
"1": "a",
"3": "b",
"8": {
"12": "c",
"25": "d"
}
}
I want to get 1,3,8as result!
我想得到1,3,8结果！
I found this code:
我找到了这个代码：
for key, value in data.iteritems():
print key, value
But it prints all keys (also 12 and 25)
但它打印所有键（还有12 和 25）
采纳答案by karthikr
Just do a simple .keys()
做一个简单的 .keys()
>>> dct = {
... "1": "a",
... "3": "b",
... "8": {
... "12": "c",
... "25": "d"
... }
... }
>>>
>>> dct.keys()
['1', '8', '3']
>>> for key in dct.keys(): print key
...
1
8
3
>>>
If you need a sorted list:
如果您需要排序列表：
keylist = dct.keys()
keylist.sort()
回答by Frambot
for key in data.keys():
print key
回答by Hafizur Rahman
A good way to check whether a python object is an instance of a type is to use isinstance()which is Python's 'built-in' function.
For Python 3.6:
检查 Python 对象是否是类型实例的一个好方法是使用isinstance()which 是 Python 的“内置”函数。对于 Python 3.6：
dct = {
"1": "a",
"3": "b",
"8": {
"12": "c",
"25": "d"
}
}
for key in dct.keys():
if isinstance(dct[key], dict)== False:
print(key, dct[key])
#shows:
# 1 a
# 3 b
回答by Praveen Manupati
As Karthik mentioned, dct.keys()will work but it will return all the keys in dict_keystype not in listtype. So if you want all the keys in a list, then list(dct.keys())will work.
正如 Karthik 所提到的，dct.keys()会起作用，但它会返回所有dict_keys类型的键，而不是list类型。所以如果你想要一个列表中的所有键，那么list(dct.keys())就可以了。
