Linux 如何在 shell 脚本中使用 curl？
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How to use curl in a shell script?
提问by san983
I'm trying to run this shell script in order to install RVM in an Ubuntu box
我正在尝试运行这个 shell 脚本，以便在 Ubuntu 机器中安装 RVM
#!/bin/bash
RVMHTTP="https://raw.github.com/wayneeseguin/rvm/master/binscripts/rvm-installer"
CURLARGS="-f -s -S -k"
bash < <(curl $CURLARGS $RVMHTTP)
but I get the following error
但我收到以下错误
Syntax error: Redirection unexpected
语法错误：重定向意外
Also tested not using the variables, but same result, could you tell what I'm missing?
也没有使用变量进行测试，但结果相同，你能告诉我我错过了什么吗？
采纳答案by Tilo
#!/bin/bash
CURL='/usr/bin/curl'
RVMHTTP="https://raw.github.com/wayneeseguin/rvm/master/binscripts/rvm-installer"
CURLARGS="-f -s -S -k"
# you can store the result in a variable
raw="$($CURL $CURLARGS $RVMHTTP)"
# or you can redirect it into a file:
$CURL $CURLARGS $RVMHTTP > /tmp/rvm-installer
or:
或者：
回答by ДМИТРИЙ МАЛИКОВ
Firstly, your example is looking quite correct and works well on my machine. You may go another way.
首先，您的示例看起来非常正确，并且在我的机器上运行良好。你可以走另一条路。
curl $CURLARGS $RVMHTTP > ./install.sh
All output now storing in ./install.shfile, which you can edit and execute.
现在所有输出都存储在./install.sh文件中，您可以编辑和执行该文件。
回答by Krunal Shah
url=”http://shahkrunalm.wordpress.com“
content=”$(curl -sLI “$url” | grep HTTP/1.1 | tail -1 | awk {‘print ′})”
if [ ! -z $content ] && [ $content -eq 200 ]
then
echo “valid url”
else
echo “invalid url”
fi
