bash 寻找匹配的“)”时出现意外的 EOF 错误
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Unexpected EOF error while looking for matching `)'
提问by CSRadical
Trying to run a bash script and while some things work correctly, I get this message:
尝试运行 bash 脚本，虽然有些事情可以正常工作，但我收到以下消息：
line 34: unexpected EOF while looking for matching `)'
Here's the code, I've marked the line in question (in the hypotenuse method):
这是代码，我已经标记了有问题的行（在斜边方法中）：
#!/bin/bash
# Bash Script Calculator
# -----------------------------------------------------
#
#
#
# -----------------------------------------------------
a=
op=""
b=
if [ $# -lt 3 ]
then
echo "{
hyp=$(bc -l << EOF #LINE 34
scale = 9
sqrt ( * + * )
EOF
^^^^---these spaces count
num1 opr num2"
echo "Operators: +,-,x,/"
exit 1
fi
case "$op" in
+) echo $(( $a + $b ));;
-) echo $(( $a - $b ));;
x) echo $(( $a * $b ));;
/) echo $(( $a / $b ));;
hyp) hypotenuse;;
area) area;;
*) echo "Error: Not a listed operator"
echo "If using multiplication, use "x"";;
esac
hypotenuse()
{
hyp=$(bc -l << EOF #LINE 34
scale = 9
sqrt ( * + * )
EOF
)
echo "$hyp"
}
area()
{
area=$(echo "scale=2;3.14 * ($a * $a)" | bc)
echo "$area"
}
Am I missing something? I've spent a little time looking things up on Google and such, nothing seems to tell me otherwise.
我错过了什么吗？我花了一点时间在谷歌等上查找东西，似乎没有什么能告诉我的。
Thanks for any help!
谢谢你的帮助！
回答by Marc B
Your heredoc terminator is wrong:
你的heredoc终止符是错误的：
##代码##Your terminator is now actually [space][space][space][space]EOF, while bash is looking for EOFWITHOUT the spaces. The terminator MUST begin at the start of the line, without any whitespace before (or after) it.
你的终结者现在实际上是[space][space][space][space]EOF，而 bash 正在寻找EOF没有空格的。终止符必须从行首开始，在它之前（或之后）没有任何空格。
Since your heredoc never terminates, bash will run right off the end of the script looking for a )which never comes, because the heredoc consumed the one you actually did have.
由于您的 heredoc 永远不会终止，bash 将在脚本的末尾运行，寻找一个)永远不会出现的，因为heredoc 消耗了您实际拥有的那个。
