在 python 中逐项划分（划分 termino a termino en python ）
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term by term division in python (division termino a termino en python )
提问by ricardo
hello all,need to define a function that can be divided term by term matrix or in the worst cases, between arrays of lists so you get the result in a third matrix,
大家好，需要定义一个函数，该函数可以按项矩阵划分，或者在最坏的情况下，在列表数组之间进行划分，以便在第三个矩阵中得到结果，
thanks for any response
感谢您的任何回应
回答by Stephan202
Unless I'm misunderstanding, this is where numpycan be put to good use:
除非我误解了，否则numpy可以很好地利用这里：
>>> from numpy import *
>>> a = array([[1,2,3],[4,5,6],[7,8,9]])
>>> b = array([[0.5] * 3, [0.5] * 3, [0.5] * 3])
>>> a / b
array([[ 2., 4., 6.],
[ 8., 10., 12.],
[ 14., 16., 18.]])
This works for multiplication too. And indeed, as noted by Mark, scalar division (and multiplication) is also possible:
这也适用于乘法。事实上，正如Mark所指出的，标量除法（和乘法）也是可能的：
>>> a / 10.0
array([[ 0.1, 0.2, 0.3],
[ 0.4, 0.5, 0.6],
[ 0.7, 0.8, 0.9]])
>>> a * 10
array([[10, 20, 30],
[40, 50, 60],
[70, 80, 90]])
Edit: to be complete, for lists of lists you could do the following:
编辑：要完整，对于列表列表，您可以执行以下操作：
>>> a = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
>>> b = [[0.5] * 3, [0.5] * 3, [0.5] * 3]
>>> def mat_div(a, b):
... return [[n / d for n, d in zip(ra, rb)] for ra, rb in zip(a, b)]
...
>>> mat_div(a, b)
[[2.0, 4.0, 6.0], [8.0, 10.0, 12.0], [14.0, 16.0, 18.0]]
