Java将二维数组传递给方法
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Java passing 2 dimension array to method
提问by Wizard
public static void main{
String [][] book = new String[100][6];
for(int i = 0; i < 1; i++) {
for(int j = 0; j < 5; j++) {
book[i][j] = i;
}
}
arrayMethod(book);
}
public static void arrayMethod(String[][] array){
System.out.println(Arrays.asList(array));
}
arrayMethod method output is[[Ljava.lang.String;@639facbc, [Ljava.lang.String;@8059dbd, [Ljava.lang.String;@28b6e768, [Ljava.lang.String;@1271ba, ....
arrayMethod 方法输出为[[Ljava.lang.String;@639facbc, [Ljava.lang.String;@8059dbd, [Ljava.lang.String;@28b6e768, [Ljava.lang.String;@1271ba, ....
Problem is that in arrayMethod I can't acces 2 dimension array data, where can be problem?
问题是在 arrayMethod 中我不能访问二维数组数据，哪里有问题？
采纳答案by chrylis -cautiouslyoptimistic-
It's doing exactly what you want: you're pretending the (first-level) array is a List(of Array) and then printing the toString()of those, which looks something like [Ljava.lang.String@pointer. You probably want this instead:
它正在做你想做的事情：你假装（第一级）数组是一个List（of Array），然后打印toString()那些看起来像[Ljava.lang.String@pointer. 你可能想要这个：
System.out.println(Arrays.deepToString(array));
回答by Fr0z3n7
as Alya'a Gamal said, if you want to put an int inside an array of String you need to parse it : book[i][j] = Integer.toString(i);.
Then if you want to display your array, you need to run thought it, like this for example :
正如 Alya'a Gamal 所说，如果你想把一个 int 放在一个 String 数组中，你需要解析它：book[i][j] = Integer.toString(i);。然后如果你想显示你的数组，你需要运行thought it，例如：
public static void arrayMethod(String[][] array){
for(int i = 0; i < array.length;i++) {
for(int j = 0; j < array[i].length;j++)
System.out.println(array[i][j]); // a stringBuilder would be better than to print inside the loop
}
}
回答by MouseLearnJava
You can use Arrays.toStringto print 1-D string array, but you CANNOTuse Arrays.toStringto print the 2-D array directly.
可以用于Arrays.toString打印一维字符串数组，但不能用于Arrays.toString直接打印二维数组。
There are 2 ways for you to print the 2D string array in console.
有两种方法可以在控制台中打印 2D 字符串数组。
Way#1 ==>
方式#1 ==>
System.out.println(Arrays.deepToString(array));
Way#2 ==>
方式#2 ==>
for(String[] arr: array)
{
System.out.println(Arrays.toString(arr));
}
回答by Sameer Sawla
I see three issues here :
我在这里看到三个问题：
(1). The signature of the main method looks odd. It would raise a compile issue.
(1). main 方法的签名看起来很奇怪。它会引发编译问题。
public static void main(String args[])
{
// Your code here
}
(2). In the following code :
(2). 在以下代码中：
for(int i = 0; i < 1; i++) {
for(int j = 0; j < 5; j++) {
book[i][j] = i;
}
}
book[i][j] =i; // Here you are trying to insert an int in place where a String is required.
This will again lead to a compile time issue.
这将再次导致编译时问题。
You can correct it as follows:
您可以按如下方式更正：
book[i][j] = Integer.toString(i);
(3).
(3).
Use the following static method in the Arraysclass to print the elements of 2D array on the console.
在Arrays类中使用以下静态方法在控制台上打印二维数组的元素。
System.out.println(Arrays.deepToString(array));
Hope this helps.
希望这可以帮助。
+1 for isolating the problem.
+1 用于隔离问题。
