git checkout 所有文件
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git checkout all the files
提问by fedorqui 'SO stop harming'
How can I get rid of all the changes in all the files of my repository?
如何摆脱存储库中所有文件中的所有更改？
Say I am in a branch and I did some changes. git statusreturns a set of files in the "Changes not staged for commit" and I notice I would like to get rid of all of these changes in all the files. How can I do this with a single command?
假设我在一个分支，我做了一些改变。git status在“未暂存的更改”中返回一组文件，我注意到我想删除所有文件中的所有这些更改。如何使用单个命令执行此操作？
I know I can do the following to checkout just one file:
我知道我可以执行以下操作来只检出一个文件：
git checkout -- <file>
I noticed that git checkout --alone returns the list of all uncommited files. However, I cannot find a way to checkout all of them, something like git checkout --all.
我注意到git checkout --只有返回所有未提交文件的列表。但是，我找不到一种方法来结帐所有这些，例如git checkout --all.
I checked man git checkoutand could not find anything. Also I saw Git: Checkout all files except oneand tried git checkout .and did not work either.
我检查过man git checkout，找不到任何东西。我还看到了Git: Checkout all files except one并尝试过git checkout .但也没有工作。
Would I have to do it programmatically, by looping through the git checkout --output?
我是否必须通过循环git checkout --输出以编程方式执行此操作？
回答by poke
If you are at the root of your working directory, you can do git checkout -- .to check-out all files in the current HEAD and replace your local files.
如果您位于工作目录的根目录，您可以git checkout -- .检出当前 HEAD 中的所有文件并替换您的本地文件。
You can also do git reset --hardto reset your working directory and replace all changes (including the index).
您还git reset --hard可以重置工作目录并替换所有更改（包括索引）。
回答by Singhak
Other way which I found useful is:
我发现有用的其他方法是：
git checkout <wildcard>
Example:
例子：
git checkout *.html
More generally:
更普遍：
git checkout <branch> <filename/wildcard>
