php - 如何修复这个非法偏移类型错误
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php - How do I fix this illegal offset type error
提问by Steven
I'm getting
我越来越
illegal offset type
非法偏移类型
error for every iteration of this code. Here's the code :
此代码的每次迭代都会出错。这是代码：
$s = array();
for($i = 0; $i < 20; $i++){
$source = $xml->entry[$i]->source;
$s[$source] += 1;
}
print_r($s)
回答by zombat
Illegal offset typeerrors occur when you attempt to access an array index using an objector an arrayas the index key.
当您尝试使用对象或数组作为索引键访问数组索引时，会发生非法偏移类型错误。
Example:
例子：
$x = new stdClass();
$arr = array();
echo $arr[$x];
//illegal offset type
Your $xmlarray contains an object or array at $xml->entry[$i]->sourcefor some value of $i, and when you try to use that as an index key for $s, you get that warning. You'll have to make sure $xmlcontains what you want it to and that you're accessing it correctly.
您的$xml数组包含一个对象或数组 at$xml->entry[$i]->source的某个值$i，当您尝试将其用作 的索引键时$s，您会收到该警告。您必须确保$xml包含您想要的内容并且您正在正确访问它。
回答by Zafer
Use trim($source)before $s[$source].
trim($source)之前 使用$s[$source]。
回答by brian_d
check $xml->entry[$i] exists and is an object before trying to get a property of it
在尝试获取它的属性之前检查 $xml->entry[$i] 是否存在并且是一个对象
if(isset($xml->entry[$i]) && is_object($xml->entry[$i])){
$source = $xml->entry[$i]->source;
$s[$source] += 1;
}
or $source might not be a legal array offset but an array, object, resource or possibly null
或 $source 可能不是合法的数组偏移量，而是数组、对象、资源或可能为 null
回答by Byron Whitlock
There are probably less than 20 entries in your xml.
您的 xml 中的条目可能少于 20 个。
change the code to this
把代码改成这样
for ($i=0;$i< sizeof($xml->entry); $i++)
...
回答by user8387356
I had a similar problem. As I got a Character from my XML child I had to convert it first to a String (or Integer, if you expect one). The following shows how I solved the problem.
我有一个类似的问题。当我从我的 XML 孩子那里得到一个字符时，我必须先将它转换为字符串（或整数，如果你期望的话）。下面显示了我是如何解决这个问题的。
foreach($xml->children() as $newInstr){
$iInstrument = new Instrument($newInstr['id'],$newInstr->Naam,$newInstr->Key);
$arrInstruments->offsetSet((String)$iInstrument->getID(), $iInstrument);
}
