python 添加/删除列表中的项目
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add/remove items in a list
提问by Jam
I'm trying to create a player who can add and remove items from their inventory. I have everything working, I just have 1 small problem. Every time it prints the inventory, 'None' also appears. I've been messing with it to try and remove that, but no matter what I do, 'None' always appears in the program! I know I'm just missing something simple, but I can't figure it out for the life of me.
我正在尝试创建一个可以从他们的库存中添加和删除项目的玩家。我一切正常,我只有 1 个小问题。每次打印清单时,也会出现“无”。我一直在弄乱它以尝试删除它,但无论我做什么,“无”总是出现在程序中!我知道我只是错过了一些简单的东西,但我一生都无法弄清楚。
class Player(object):
def __init__(self, name, max_items, items):
self.name=name
self.max_items=max_items
self.items=items
def inventory(self):
for item in self.items:
print item
def take(self, new_item):
if len(self.items)<self.max_items:
self.items.append(new_item)
else:
print "You can't carry any more items!"
def drop(self, old_item):
if old_item in self.items:
self.items.remove(old_item)
else:
print "You don't have that item."
def main():
player=Player("Jimmy", 5, ['sword', 'shield', 'ax'])
print "Max items:", player.max_items
print "Inventory:", player.inventory()
choice=None
while choice!="0":
print \
"""
Inventory Man
0 - Quit
1 - Add an item to inventory
2 - Remove an item from inventory
"""
choice=raw_input("Choice: ")
print
if choice=="0":
print "Good-bye."
elif choice=="1":
new_item=raw_input("What item would you like to add to your inventory?")
player.take(new_item)
print "Inventory:", player.inventory()
elif choice=="2":
old_item=raw_input("What item would you like to remove from your inventory?")
player.drop(old_item)
print "Inventory:", player.inventory()
else:
print "\nSorry, but", choice, "isn't a valid choice."
main()
raw_input("Press enter to exit.")
采纳答案by dmazzoni
The problem is this statement:
问题是这个语句:
print "Inventory:", player.inventory()
You're telling Python to print the value returned from player.inventory(). But your inventory() method just prints the inventory, it doesn't return anything - so the return value is implicitly None.
您告诉 Python 打印从 player.inventory() 返回的值。但是您的inventory() 方法只是打印库存,它不返回任何内容-因此返回值隐式为None。
You probably want to explicitly choose either this:
您可能希望明确选择以下任一选项:
print "Inventory:"
player.print_inventory()
Or alternatively you could have it return a string and do this:
或者,您可以让它返回一个字符串并执行以下操作:
print "Inventory:", player.inventory_as_str()
回答by Nope
Would you mind replacing the function:
你介意更换这个功能吗:
def inventory(self):
for item in self.items:
print item
with this:
有了这个:
def inventory(self):
print self.items
and then call:
然后调用:
print "Inventory"
player.inventory()
Or you could have the function:
或者你可以拥有以下功能:
def print_inventory(self):
print "Inventory:"
for item in self.items:
print item