ruby 如何将字符串拆分为多个单词的数组？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/15914614/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How do I split string into array of multiple words?
提问by sharataka
I have a string that I'm using .split(' ') on to split up the string into an array of words. Can I use a similar method to split the string into an array of 2 words instead?
我有一个字符串，我正在使用 .split(' ') 将字符串拆分为一个单词数组。我可以使用类似的方法将字符串拆分为 2 个单词的数组吗？
Returns an array where each element is one word:
返回一个数组，其中每个元素都是一个单词：
words = string.split(' ')
I'm looking to return an array where each element is 2 words instead.
我希望返回一个数组，其中每个元素都是 2 个单词。
采纳答案by Frambot
str = 'one two three four five six seven'
str.split.each_slice(2).map{|a|a.join ' '}
=> ["one two", "three four", "five six", "seven"]
This also handles the case of an odd number of words.
这也处理奇数个单词的情况。
回答by oldergod
You can do
你可以做
string= 'one1! two2@ three3# four4$ five5% six6^ sev'
string.scan(/\S+ ?\S*/)
# => ["one1! two2@", "three3# four4$", "five5% six6^", "sev"]
回答by Hew Wolff
Something like this should work:
这样的事情应该工作：
string.scan(/\w+ \w+/)
回答by the Tin Man
Ruby's scanis useful for this:
Rubyscan对此很有用：
'a b c'.scan(/\w+(?:\s+\w+)?/)
=> ["a b", "c"]
'a b c d e f g'.scan(/\w+(?:\s+\w+)?/)
=> ["a b", "c d", "e f", "g"]
回答by Piece Digital
This is all I had to do:
这就是我所要做的：
def first_word
chat = "I love Ruby"
chat = chat.split(" ")
chat[0]
end
