在 Laravel 中将依赖参数传递给 App::make() 或 App::makeWith()
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Passing dependency parameters to App::make() or App::makeWith() in Laravel
提问by jd182
I have a class that uses a dependency. I need to be able to dynamically set parameters on the dependency from the controller:
我有一个使用依赖项的类。我需要能够在控制器的依赖项上动态设置参数：
$objDependency = new MyDependency();
$objDependency->setSomething($something);
$objDependency->setSomethingElse($somethingElse);
$objMyClass = new MyClass($objDependency);
How do I achieve this through the Service Container in Laravel? This is what I've tried but this seems wrong to me. In my AppServiceProvider:
我如何通过 Laravel 中的服务容器实现这一点？这是我尝试过的，但这对我来说似乎是错误的。在我的 AppServiceProvider 中：
$this->app->bind('MyClass', function($app,$parameters){
$objDependency = new MyDependency();
$objDependency->setSomething($parameters['something']);
$objDependency->setSomethingElse($parameters['somethingElse']);
return new MyClass($objDependency);
}
And then in the controller i'd use this like:
然后在控制器中我会这样使用：
$objMyClass = App:make('MyClass', [
'something' => $something,
'somethingElse' => $somethingElse
]);
Is this correct? Is there a better way I can do this?
这样对吗？有没有更好的方法可以做到这一点？
Thanks
谢谢
回答by realplay
You can see detailed documentation here: https://laravel.com/docs/5.6/container#the-make-method
您可以在此处查看详细文档：https: //laravel.com/docs/5.6/container#the-make-method
It's done like this:
它是这样完成的：
$api = $this->app->makeWith('HelpSpot\API', ['id' => 1]);
Or use the app() helper
或者使用 app() 助手
$api = app()->makeWith(HelpSpot\API::class, ['id' => 1]);
It is essentialto set the array key as the argument variable name, otherwise it will be ignored. So if your code is expecting a variable called $modelData, the array key needs to be 'modelData'.
这是必要的设置数组键作为参数变量名，否则会被忽略。因此，如果您的代码需要一个名为 $modelData 的变量，则数组键必须为 'modelData'。
$api = app()->makeWith(HelpSpot\API::class, ['modelData' => $modelData]);
Note: if you're using it for mocking, makeWith does not return Mockery instance.
注意：如果你用它来模拟，makeWith 不会返回 Mockery 实例。
回答by wired00
You can also do it this way:
你也可以这样做：
$this->app->make(SomeClass::class, ["foo" => 'bar']);
