Java：XML 规范化
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Java: XML canonicalization
提问by Ivan
What's the easiest way to make a canonical form of a XML file in Java? Do you have some done code for that? I've found several links on the net, like this, this, and this, but I can't make it to work :/
在 Java 中制作规范形式的 XML 文件的最简单方法是什么？你有一些完成的代码吗？我在网上找到了几个链接，比如这个、这个和这个，但我不能让它工作：/
Thanks,
谢谢，
Ivan
伊万
EDIT: I used the canonicalizer that was proposed down there, but I get strange results. To be more precize, this method doesn't delete white spaces between elements... This is what I get:
编辑：我使用了那里提出的规范化程序，但我得到了奇怪的结果。更准确地说，此方法不会删除元素之间的空格......这就是我得到的：
<Metric xmlns="http://www.ibm.com/wsla" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" name="total_memory_consumption_metric" type="double" unit="Mbit" xsi:schemaLocation="http://www.ibm.com/wsla WSLA.xsd"> <Source>ServiceProvider</Source> <MeasurementDirective resultType="double" xsi:type="StatusRequest"> <RequestURI> ***unused*** </RequestURI> </MeasurementDirective> </Metric>
回答by eolith
The Canonicalizerclass at Apache XML Security project:
Apache XML Security 项目中的Canonicalizer类：
org.apache.xml.security.Init.init(); //
Canonicalizer canon = Canonicalizer.getInstance(Canonicalizer.ALGO_ID_C14N_OMIT_COMMENTS);
byte canonXmlBytes[] = canon.canonicalize(yourXmlBytes);
String canonXmlString = new String(canonXmlBytes);
回答by David Moles
Another option is nu.xom.canonical.Canonicalizerif you're using XOM, or if you don't otherwise have a need for Apache XML Security.
如果您正在使用 XOM，或者如果您不需要 Apache XML 安全性，则另一个选择是nu.xom.canonical.Canonicalizer。
