jQuery 重新填充下拉列表选项,如何清除选项列表然后重新填充?

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时间:2020-08-26 16:44:09  来源:igfitidea点击:

Re-populate drop down list options, how to clear options list and then re-populate?

jqueryajax

提问by Blankman

Re-populate drop down list options, how to clear options list and then re-populate?

重新填充下拉列表选项,如何清除选项列表然后重新填充?

When a event fires, I need to wipe out the current contents of the drop down list #users, and then re-populate it via ajax.

当事件触发时,我需要清除下拉列表#users 的当前内容,然后通过ajax 重新填充它。

My ajax call is returning the HTML for the options like:

我的 ajax 调用正在返回以下选项的 HTML:

<option name=blah1>text1</option>
<option name=blah2>text2</option>
<option name=blah3>text3</option>

回答by kobe

you can use the below

你可以使用下面的

$('#mySelect').empty()

and then rebind the new data.

然后重新绑定新数据。

回答by hunter

You can just change the htmlof the selectelement using the data returned from your ajax call

你可以只改变html了的select利用你的Ajax调用返回的数据元素

$("#users").html(data);

so it would look something like this:

所以它看起来像这样:

$.ajax({
    type: "POST",
    url: url,
    data: data,
    success: : function(data) {
        $("#users").html(data);
    }
    dataType: "HTML"
});

回答by Gajendra Bang

function(ajaxResult) {
   $('#users').html(""); //clear old options
   $('#users').html(ajaxResult);
}

回答by shoebox639

In the call back of your AJAX call, just clear out the contents of your select element and re-add those returned by the AJAX call.

在 AJAX 调用的回调中,只需清除 select 元素的内容并重新添加 AJAX 调用返回的内容。

function(ajaxResult) {
   $('#users').html(ajaxResult);
}