php 如何比较两个数组并从一个数组中删除匹配的元素以进行下一个循环?

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时间:2020-08-24 21:59:12  来源:igfitidea点击:

How to compare two arrays and remove matching elements from one for the next loop?

phparrays

提问by kevtrout

How else might you compare two arrays ($A and $B )and reduce matching elements out of the first to prep for the next loop over the array $A?

您还可以如何比较两个数组($A 和 $B )并减少第一个数组中的匹配元素,以便为数组 $A 上的下一个循环做准备?

$A = array(1,2,3,4,5,6,7,8);
$B = array(1,2,3,4);

$C = array_intersect($A,$B);  //equals (1,2,3,4)
$A = array_diff($A,$B);       //equals (5,6,7,8)

Is this the simplest way or is there a way to use another function that I haven't thought of? My goal is to have an array that I can loop over, pulling out groups of related content (I have defined those relationships elsewhere) until the array returns false.

这是最简单的方法还是有一种方法可以使用我没有想到的另一个功能?我的目标是拥有一个可以循环的数组,提取相关内容组(我已经在别处定义了这些关系),直到数组返回 false。

回答by rg88

You've got it. Just use array_diffor array_intersect. Doesn't get much easier than that.

你已经知道了。只需使用array_diffarray_intersect。没有比这更容易的了。

Edit:For example:

编辑:例如:

$arr_1 = array_diff($arr_1, $arr_2);
$arr_2 = array_diff($arr_2, $arr_1);

Source

来源

回答by Kalpesh Bhaliya

Dear easy and clean way

亲爱的简单干净的方式

$clean1 = array_diff($array1, $array2); 
$clean2 = array_diff($array2, $array1); 
$final_output = array_merge($clean1, $clean2);

回答by warren

See also array_unique. If you concatenate the two arrays, it will then yank all duplicates.

另请参阅array_unique。如果将两个数组连接起来,它将删除所有重复项。

回答by rg88

Hey, even better solution: array _ uintersect.This let's you compare the arrays as per array_intersect but then it lets you compare the data with a callback function.

嘿,更好的解决方案:array _ uintersect。这让您可以根据 array_intersect 比较数组,但随后您可以将数据与回调函数进行比较。

回答by Ashfaq Hussain

Try to this

试试这个

$a = array(0=>'a',1=>'x',2=>'c',3=>'y',4=>'w');
$b = array(1=>'a',6=>'b',2=>'y',3=>'z');
$c = array_intersect($a, $b);

$result = array_diff($a, $c);
print_r($result);