Python 将列表的元素提升到幂
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Raising elements of a list to a power
提问by Amelia155
How can I raise the numbers in list to a certain power?
如何将列表中的数字提高到一定的幂？
采纳答案by Jorick Spitzen
Use list comprehension:
使用列表理解：
def power(my_list):
return [ x**3 for x in my_list ]
https://docs.python.org/3.4/tutorial/datastructures.html#list-comprehensions
https://docs.python.org/3.4/tutorial/datastructures.html#list-comprehensions
回答by maggick
You can simply do:
你可以简单地做：
numbers=[1,2,3,4,5,6,7,8,9]
numbers3 = []
for n in numbers:
numbers3.append(n**3)
print('Original list:', numbers)
print('Cubic list:', numbers3)
回答by konart
def turn_to_power(list, power=1):
return [number**power for number in list]
Example:
例子：
list = [1,2,3]
turn_to_power(list)
=> [1, 2, 3]
turn_to_power(list,2)
=> [1, 4, 9]
UPD: you should also consider reading about pow(x,y)function of mathlib: https://docs.python.org/3.4/library/math.html
UPD：您还应该考虑阅读有关libpow(x,y)功能的信息math：https: //docs.python.org/3.4/library/math.html
回答by GiovanniPi
Actually your script do what you want, and that is the result (keep in mind that you are applying the power function to [1,2,3,4,5,6,7,8,9])
实际上你的脚本做你想做的，这就是结果（请记住，你正在将幂函数应用于 [1,2,3,4,5,6,7,8,9]）
('Cubic list:', [1, 8, 27, 64, 125, 216, 343, 512, 729])
('立方表:', [1, 8, 27, 64, 125, 216, 343, 512, 729])
Your problem is that you also modified the original list, due to the nature on the list type in python. If you want to keep also your original list you should pass a copy of it to your function. You can do it like this
您的问题是由于python中列表类型的性质，您还修改了原始列表。如果您还想保留原始列表，则应将其副本传递给您的函数。你可以这样做
def main():
numbers=[1,2,3,4,5,6,7,8,9]
numbers3=power(numbers[:])
print('Original list:', numbers)
print('Cubic list:', numbers3)
回答by dermen
Use a list comprehension for some increased speed:
使用列表理解来提高速度：
print('Original list:', numbers)
print('Cubic list:', [n**3 for n in numbers])
回答by tommy.carstensen
Nobody has mentioned mapand functools.partialand the accepted answer does not mention pow, but for the sake of completeness I am posting this solution:
没有人提到map并且functools.partial接受的答案没有提到pow，但为了完整起见，我发布了这个解决方案：
import functools
bases = numbers = [1,2,3]
power = exponent = 3
cubed = list(map(functools.partial(pow, exponent), numbers))
I would use a list comprehension myself as suggested, but I think functools.partialis a very cool function that deserves to be shared. I stole my answer from @sven-marnach hereby the way.
我会按照建议自己使用列表理解，但我认为这functools.partial是一个非常酷的函数，值得分享。顺便说一下，我从@sven-marnach 那里偷了我的答案。
回答by Robert Calhoun
Another mappattern, using lambdainstead of function.partial():
另一种map模式，使用lambda代替function.partial()：
numbers=[1,2,3,4]
squares=list(map(lambda x:pow(x,2),numbers))
print(squares)
