php 运行 json_encode 后替换 \r\n（换行符）
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Replacing \r\n (newline characters) after running json_encode
提问by Robbie Trencheny
So when I run json_encode, it grabs the \r\n from MySQL aswell. I have tried rewriting strings in the database to no avail. I have tried changing the encoding in MySQL from the default latin1_swedish_ci to ascii_bin and utf8_bin. I have done tons of str_replace and chr(10), chr(13) stuff. I don't know what else to say or do so I'm gonna just leave this here....
因此，当我运行 json_encode 时，它也会从 MySQL 中获取 \r\n。我试过重写数据库中的字符串无济于事。我尝试将 MySQL 中的编码从默认的 latin1_swedish_ci 更改为 ascii_bin 和 utf8_bin。我已经做了大量的 str_replace 和 chr(10), chr(13) 的东西。我不知道还能说什么或做什么，所以我要把这个留在这里......
$json = json_encode($new);
if(isset($_GET['pretty'])) {
echo str_replace("\/", "/", jsonReadable(parse($json)));
} else {
$json = str_replace("\/", "/", $json);
echo parse($json);
}
The jsonReadable function is from hereand the parse function is from here. The str_replaces that are already in there are because I am getting weird formatted html tags like </h1>. Finally, $new is an array which is crafted above. Full code upon request.
jsonReadable 函数来自这里，解析函数来自这里。已经在那里的 str_replaces 是因为我得到了像 </h1> 这样奇怪的格式化 html 标签。最后，$new 是一个上面精心制作的数组。应要求提供完整代码。
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采纳答案by Frankie
Does the string contain "\r\n" (as in 0x0D 0x0A) or the literal string '\r\n'? If it's the former, this should remove any newlines.
字符串是否包含“\r\n”（如 0x0D 0x0A）或文字字符串 '\r\n'？如果是前者，这应该删除任何换行符。
$json = preg_replace("!\r?\n!", "", $json);
Optionally, replace the second parameter "" with "<br />" if you'd like to replace the newlines with a br tag. For the latter case, try the following:
或者，如果您想用 br 标签替换换行符，请将第二个参数“”替换为“<br />”。对于后一种情况，请尝试以下操作：
$json = preg_replace('!\r?\n!', "", $json);
回答by Ignacio Vazquez-Abrams
Don't replace it in the JSON, replace it in the source before you encode it.
不要在 JSON 中替换它，在编码之前在源中替换它。
回答by Kyle Hudson
I had a similar issue, i used:
我有一个类似的问题，我用过：
$p_num = trim($this->recp);
$p_num = str_replace("\n", "", $p_num);
$p_num = str_replace("\r", ",", $p_num);
$p_num = str_replace("\n",',', $p_num);
$p_num = rtrim($p_num, "\x00..\x1F");
Not sure if this will help with your requirements.
不确定这是否有助于满足您的要求。
