C语言 MIPS汇编语言中“move”和“li”的区别
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Difference between "move" and "li" in MIPS assembly language
提问by user2492270
I was practicing converting C code into MIPS assembly language, and am having trouble understanding the usage of moveand liin variable assignment.
我正在练习将 C 代码转换为 MIPS 汇编语言，但在理解变量赋值中move和的用法时遇到了麻烦li。
For example, to implement the following C line in MIPS:
例如，要在 MIPS 中实现以下 C 行：
int x = 0;
If I understand it correctly (I highly doubt this, though), it looks like both of these work in MIPS assembler:
如果我理解正确（不过我对此表示高度怀疑），看起来这两个都可以在 MIPS 汇编器中工作：
move $s0, $zero
li $s0, $zero
Am I wrong? What is the difference between these two lines?
我错了吗？这两条线有什么区别？
回答by duskwuff -inactive-
The moveinstruction copies a value from one register to another. The liinstruction loads a specific numeric value into that register.
该move指令将值从一个寄存器复制到另一个寄存器。该li指令将特定数值加载到该寄存器中。
For the specificcase of zero, you can use either the constant zero or the zero register to get that:
对于零的特定情况，您可以使用常量零或零寄存器来获得：
move $s0, $zero
li $s0, 0
There's no register that generates a value other than zero, though, so you'd have to use liif you wanted some other number, like:
但是，没有寄存器可以生成零以外的值，因此li如果您想要其他数字，则必须使用，例如：
li $s0, 12345678
