从 PHP 类中的另一个函数调用一个函数

Call one function from another function in PHP class

提问by vili

I want to scan directories and subdirectories, make list of xml files, take content from xml files and display it. This functions work correctly without OOP. I try to create a class. I call function scandir_throughfrom function main. I haven't errors, result too.

我想扫描目录和子目录，制作 xml 文件列表，从 xml 文件中获取内容并显示它。此函数无需 OOP 即可正常工作。我尝试创建一个类。我scandir_through从 function调用function main。我没有错误，结果也是。

class data {
    var $dir = 'D:\wamp4\www\begin';

    public function scandir_through($dir)
     {
         $items = glob($dir . '/*');
         for ($i = 0; $i < count($items); $i++) {
             if (is_dir($items[$i])) {
                 $add = glob($items[$i] . '/*');
                 $items = array_merge($items, $add);
             }
         }
        return $items;
     }

    public function main()
    {
        $scan_tree = $this->scandir_through($dir);
        echo "<ul id='booklist'>"."</n>";
        foreach ($scan_tree as $key=>$file){
            $url = $file;
            $xml = simplexml_load_file($url);  
               $book_count = count($xml->book); 
               for($i = 0; $i < $book_count; $i++) { 
                   $book = $xml->book[$i]; 
                   $title=$xml->book[$i]->title;
                   $author=$xml->book[$i]->author;
                   //echo '</br>';
                   //echo $file. " &nbsp   ";
                   //echo $title. " &nbsp   ";
                   //echo $author;
                   echo "<li><div class='file'>".$file."</div>
                   <div class='title'>".$title."</div>
                   <div class='author'>".$author."</div></li></n>";
               }     
         }  
          echo "</ul>";
    }
}
$d = new data();
$d->main();
?>

回答by John Parker

The problem is because the $dirinstance variable isn't what you're accessing within your main method. (It's looking for a $dirvariable in the scope of that method, rather than at the class level.)

问题是因为$dir实例变量不是您在主方法中访问的。（它正在$dir该方法的范围内寻找一个变量，而不是在类级别。）

What you need to use is...

你需要使用的是...

$scan_tree = $this->scandir_through($this->dir);

If you turn on E_NOTICE warnings, you'll see that it'll have been throwing an error.

如果您打开 E_NOTICE 警告，您会看到它一直在抛出错误。

回答by user1522901

I think that $dir should be an argument for main. Just think if you had nothing else in the class, where would main get $dir from?

我认为 $dir 应该是 main 的一个论点。试想一下，如果你在课堂上没有其他东西， main 会从哪里得到 $dir ？

I would change:

我会改变：

public function main()

to

到

public function main($dir)

and when you call main using $d, include the dir so change that to:

当您使用 $d 调用 main 时，请包含目录，以便将其更改为：

$d->main($dir);

回答by Pichitron

$items=data::scandir_through($dir);