java 如何确定字符串中的最大值数？
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How do I determine the largest value number in a String?
提问by user1393500
Consider the following String:
考虑以下字符串：
String test= "0, 1, 3, 2, 2, 1, 1, 4, 2, 5, 1, 1, 0, 1, 241";
The largest value is the last value, 241. How do I get the count, 15, of this number within the String, as 241 is the 15th number in the String, and the largest number in the row?
最大值是最后一个值，241。我如何获得15字符串中这个数字的计数，因为 241 是字符串中的第 15 个数字，也是该行中的最大数字？
Second example:
第二个例子：
String test= "0, 1, 3, 2, 2, 1, 1, 4, 30, 5, 1, 1, 0, 1, 5";
The result should be 9 as 30 is the largest number and in the 9th place in the String.
结果应该是 9，因为 30 是最大的数字，并且在字符串中排在第 9 位。
回答by Krauxe
In the following example, the maxIndexvariable will contain the index of the highest value in the array and the actual position will be maxIndex + 1, which is what you are looking for.
在以下示例中，maxIndex变量将包含数组中最高值的索引，实际位置将为maxIndex + 1，这就是您要查找的位置。
String test = "0, 1, 3, 2, 2, 1, 1, 4, 2, 5, 1, 1, 0, 1, 241";
String[] testArray = test.split(", ");
int max = Integer.MIN_VALUE, maxIndex = 0;
for (int i = 0; i < testArray.length; i++) {
if (Integer.parseInt(testArray[i]) > max) {
max = Integer.parseInt(testArray[i]);
maxIndex = i;
}
}
Edit: initialized the other variables, and corrected some code thanks to comments
编辑：初始化其他变量，并通过注释更正了一些代码
回答by Blackbelt
split the string with String.split(",");it will return an array. Look for the max inside that array
用String.split(",");它拆分字符串将返回一个数组。在该数组中查找最大值
回答by Michal Borek
You should split this string with ,, then find the biggest one in an array. You will get the biggest number string that can be applied to find in given string.
你应该用 分割这个字符串,，然后找到数组中最大的一个。您将获得可用于在给定字符串中查找的最大数字字符串。
回答by Basim Sherif
try splitting your string into an array like this,Then find the largest number postion from that array
尝试将您的字符串拆分为这样的数组，然后从该数组中找到最大的数字位置
String[] YourArray=this.split(",");
int largest = YourArray[0];
int largestpos;
for(i = 0; i < YourArray.length; i++){
if(Integer.parseint(YourArray[i]) > largest){
largest = YourArray[i];
largestpos=i;// This is what you need
}
}
回答by SilentBomb
1) You split your string and put it into an array (of int type) 2) Then you can use any kind of Sorting provided by JAVA API(s). 3) You will find your desired output.
1) 您拆分字符串并将其放入一个数组 (int 类型) 2) 然后您可以使用 JAVA API(s) 提供的任何类型的排序。3) 你会找到你想要的输出。
回答by Mena
Quick and ugly:
又快又丑：
String initialString = "0, 1, 3, 2, 2, 1, 1, 4, 2, 5, 1, 1, 0, 1, 241";
String[] sArray = initialString.split(", ");
List<Integer> iList = new ArrayList<Integer>();
for (String s: sArray) {
iList.add(Integer.parseInt(s));
}
Collections.sort(iList);
// finding last item's value
System.out.println(iList.get(iList.size() - 1));
// now finding index
System.out.println(iList.indexOf(Integer.parseInt("241")));
Output:
输出：
241
14
The second output gives you the index of the largest Integer parsed.
Note: not checking for NumberFormatExceptionhere for simplicity.
第二个输出为您提供解析的最大整数的索引。注意：NumberFormatException为了简单起见，这里不检查。
Better solution:
更好的解决方案：
Still use String.splitand a List, but implement your own Comparator.
仍然使用String.splitand a List，但实现您自己的Comparator.
回答by xagyg
int max = Integer.MIN_VALUE, pos=0, i=0;
for (String s : test.split(",")) {
if (Integer.parseInt(s) > max) { max = Integer.parseInt(s); pos = i; }
++i;
}
System.out.println("Position of max value is: " + (pos+1));
