Python 如何获取从用户输入中输入的变量的值？
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How to get value of variable entered from user input?
提问by Nick W.
I am trying to create a basic menu that checks to see if the variable entered matches a defined variable. If the variable is defined get the data of the defined variable.
我正在尝试创建一个基本菜单，用于检查输入的变量是否与定义的变量匹配。如果定义了变量，则获取定义变量的数据。
Example.
例子。
Item1 = "bill"
Item2 = "cows"
item3 = "abcdef"
Choose_Item = input("Select your item: ")
- I type in
Item1 Choose_Itemshould equal"bill"
- 我输入
Item1 Choose_Item应该等于"bill"
采纳答案by Dougal
This seems like what you're looking for:
这似乎是你要找的：
Choose_Item = eval(input("Select your item: "))
This probably isn't the best strategy, though, because a typo or a malicious user can easily crash your code, overload your system, or do any other kind of nasty stuff they like. For this particular case, a better approach might be
不过，这可能不是最好的策略，因为打字错误或恶意用户很容易使您的代码崩溃、系统过载或做任何他们喜欢的令人讨厌的事情。对于这种特殊情况，更好的方法可能是
items = {'item1': 'bill', 'item2': 'cows', 'item3': 'abcdef'}
choice = input("Select your item: ")
if choice in items:
the_choice = items[choice]
else:
print("Uh oh, I don't know about that item")
回答by Dave Lasley
Two ways you could go about this. The bad way:
有两种方法可以解决这个问题。坏方法：
print(eval(Choose_Item))
The better way would be to use a dictionary
更好的方法是使用字典
items = {'1':'bill','2':'cows'}
Choose_Item = input("Select your Item: ")
try:
print(items[Choose_Item])
except KeyError:
print('Item %s not found' % Choose_Item)
回答by Borealid
You'll need to use locals()[Choose_Item]if you want to choose a variable whose name is what the user produced.
你需要使用locals()[Choose_Item]，如果你想选择一个变量，其名称是用户产生的内容。
A more conventional way to do this, though, is to use a dictionary:
不过，一种更传统的方法是使用字典：
items = {
'Item1': 'bill',
'Item2': 'cows',
'Item3': 'abcdef',
}
... and then the value you want is items[Choose_Item].
...然后你想要的值是items[Choose_Item].
