如何使用 Java 正则表达式拆分此字符串
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How to split this string using Java Regular Expressions
提问by Arun P Johny
I want to split the string
我想拆分字符串
String fields = "name[Employee Name], employeeno[Employee No], dob[Date of Birth], joindate[Date of Joining]";
to
到
name
employeeno
dob
joindate
I wrote the following java code for this but it is printing only name other matches are not printing.
我为此编写了以下 java 代码，但它仅打印名称，其他匹配项未打印。
String fields = "name[Employee Name], employeeno[Employee No], dob[Date of Birth], joindate[Date of Joining]";
Pattern pattern = Pattern.compile("\[.+\]+?,?\s*" );
String[] split = pattern.split(fields);
for (String string : split) {
System.out.println(string);
}
What am I doing wrong here?
我在这里做错了什么？
Thank you
谢谢
回答by Bart Kiers
This part:
这部分：
\[.+\]
matches the first [, the .+then gobbles up the entire string (if no line breaks are in the string) and then the \\]will match the last ].
匹配第一个[，.+然后吞噬整个字符串（如果字符串中没有换行符），然后\\]将匹配最后一个]。
You need to make the .+reluctant by placing a ?after it:
您需要.+通过?在它后面放置一个来使不情愿：
Pattern pattern = Pattern.compile("\[.+?\]+?,?\s*");
And shouldn't \\]+?just be \\]?
不应该\\]+?只是\\]？
回答by Mark Byers
回答by Philipp Jardas
There's an online regular expression tester at http://gskinner.com/RegExr/?2sa45that will help you a lot when you try to understand regular expressions and how they are applied to a given input.
http://gskinner.com/RegExr/?2sa45上有一个在线正则表达式测试器，当您尝试理解正则表达式以及它们如何应用于给定输入时，它将对您有很大帮助。
回答by r0ng
WOuld it be better to use Negated Character Classesto match the square brackets? \[(\w+\s)+\w+[^\]]\]
使用否定字符类来匹配方括号会更好吗？\[(\w+\s)+\w+[^\]]\]
You could also see a good example how does using a negated character class work internally (without backtracking)?
您还可以看到一个很好的例子，在内部使用否定字符类是如何工作的（没有回溯）？
