php 用于获取日期范围内的所有星期一的php函数
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php function for get all mondays within date range
提问by Nisha
Example:
$startDateis Monday 2007-02-05 and $endDateis Tuesday 2007-02-20. Then I want it to list:
示例：
$startDate是 2007-02-05 星期一和$endDate2007-02-20 星期二。然后我希望它列出：
Monday 2007-02-05
Monday 2007-02-12
Monday 2007-02-19
I looked at the PHP manual and found this to get all the days between two dates. But how to do it the way i want? PHP Code:
我查看了 PHP 手册，发现它可以获取两个日期之间的所有天数。但是如何按照我想要的方式做呢？PHP代码：
回答by Paul
Rather than get all days and loop through them all, get the first Monday after the start date and then iterate 7 days at a time:
与其获取所有天数并遍历它们，不如获取开始日期之后的第一个星期一，然后一次迭代 7 天：
$endDate = strtotime($endDate);
for($i = strtotime('Monday', strtotime($startDate)); $i <= $endDate; $i = strtotime('+1 week', $i))
echo date('l Y-m-d', $i);
回答by Stafox
I needed the same and created a simple method.
我需要同样的方法并创建了一个简单的方法。
public function getMondaysInRange($dateFromString, $dateToString)
{
$dateFrom = new \DateTime($dateFromString);
$dateTo = new \DateTime($dateToString);
$dates = [];
if ($dateFrom > $dateTo) {
return $dates;
}
if (1 != $dateFrom->format('N')) {
$dateFrom->modify('next monday');
}
while ($dateFrom <= $dateTo) {
$dates[] = $dateFrom->format('Y-m-d');
$dateFrom->modify('+1 week');
}
return $dates;
}
Then use it.
然后使用它。
$dateFromString = '2007-02-05';
$dateToString = '2007-02-20';
var_dump($this->getMondaysInRange($dateFromString, $dateToString));
Result:
结果：
array (size=3)
0 => string '2007-02-05' (length=10)
1 => string '2007-02-12' (length=10)
2 => string '2007-02-19' (length=10)
Maybe it will be helpful for somebody.
也许这对某人有帮助。
回答by NASEEM FASAL
You can use below function to get a array of dates between a date range of specific day.
您可以使用下面的函数来获取特定日期的日期范围之间的日期数组。
You have to input start date, end date and day number in number.The day number is as follow. 1 = Monday, 2 = Tuesday, 3 = Wednesday, 4 = Thursday. 5 = Friday, 6 = Saturday, 7 = Sunday.
您必须在 number 中输入开始日期、结束日期和天数。天数如下。1 = 星期一，2 = 星期二，3 = 星期三，4 = 星期四。5 = 周五，6 = 周六，7 = 周日。
function getDateForSpecificDayBetweenDates($startDate,$endDate,$day_number){
$endDate = strtotime($endDate);
$days=array('1'=>'Monday','2' => 'Tuesday','3' => 'Wednesday','4'=>'Thursday','5' =>'Friday','6' => 'Saturday','7'=>'Sunday');
for($i = strtotime($days[$day_number], strtotime($startDate)); $i <= $endDate; $i = strtotime('+1 week', $i))
$date_array[]=date('Y-m-d',$i);
return $date_array;
}
回答by Dan Grossman
for ($i = strtotime($startDate); $i <= strtotime($endDate); $i = strtotime('+1 day', $i)) {
if (date('N', $i) == 1) //Monday == 1
echo date('l Y-m-d', $i); //prints the date only if it's a Monday
}
回答by Barkati.med
i Create A class, You get All Days In range Date Group By Name of Day:
我创建一个类，你得到所有日期范围内的日期组按日期名称：
class DayHelper{
const MONDAY = 'Mon';
const TUESDAY = 'Tue';
const WEDENSDAY = 'Wed';
const THURSDAY = 'Thu';
const FRIDAY = 'Fri';
const SATURDAY = 'Sat';
const SUNDAY = 'Sun';
public function GetYeardays($dateStart, $dateend){
$period = new \DatePeriod(
new \DateTime($dateStart), new \DateInterval('P1D'), (new \DateTime($dateend))
);
$dates = iterator_to_array($period);
$arrayreturn = array();
foreach ($dates as $val) {
$date = $val->format('Y-m-d'); //format date
$get_name = date('l', strtotime($date)); //get week day
$day_name = substr($get_name, 0, 3); // Trim day name to 3 chars
switch ($day_name) {
case self::MONDAY:
$MONDAY[] = $date;
$arrayreturn[self::MONDAY] = $MONDAY;
break;
case self::TUESDAY:
$TUESDAY[] = $date;
$arrayreturn[self::TUESDAY] = $TUESDAY;
break;
case self::WEDENSDAY:
$WEDENSDAY[] = $date;
$arrayreturn[self::WEDENSDAY] = $WEDENSDAY;
break;
case self::THURSDAY:
$THURSDAY[] = $date;
$arrayreturn[self::THURSDAY] = $THURSDAY;
break;
case self::FRIDAY:
$FRIDAY[] = $date;
$arrayreturn[self::FRIDAY] = $FRIDAY;
break;
case self::SATURDAY:
$SATURDAY[] = $date;
$arrayreturn[self::SATURDAY] = $SATURDAY;
break;
case self::SUNDAY:
$SUNDAY[] = $date;
$arrayreturn[self::SUNDAY] = $SUNDAY;
break;
}
}
return $arrayreturn;
}
}
The Output will be like this
输出将是这样的
array (size=7)
'Fri' =>
array (size=5)
0 => string '2016/01/01' (length=10)
1 => string '2016/01/08' (length=10)
2 => string '2016/01/15' (length=10)
3 => string '2016/01/22' (length=10)
4 => string '2016/01/29' (length=10)
'Sat' =>
array (size=5)
0 => string '2016/01/02' (length=10)
1 => string '2016/01/09' (length=10)
2 => string '2016/01/16' (length=10)
3 => string '2016/01/23' (length=10)
4 => string '2016/01/30' (length=10)
'Sun' =>
array (size=4)
0 => string '2016/01/03' (length=10)
1 => string '2016/01/10' (length=10)
2 => string '2016/01/17' (length=10)
3 => string '2016/01/24' (length=10)
'Mon' =>
array (size=4)
0 => string '2016/01/04' (length=10)
1 => string '2016/01/11' (length=10)
2 => string '2016/01/18' (length=10)
3 => string '2016/01/25' (length=10)
'Tue' =>
array (size=4)
0 => string '2016/01/05' (length=10)
1 => string '2016/01/12' (length=10)
2 => string '2016/01/19' (length=10)
3 => string '2016/01/26' (length=10)
'Wed' =>
array (size=4)
0 => string '2016/01/06' (length=10)
1 => string '2016/01/13' (length=10)
2 => string '2016/01/20' (length=10)
3 => string '2016/01/27' (length=10)
'Thu' =>
array (size=4)
0 => string '2016/01/07' (length=10)
1 => string '2016/01/14' (length=10)
2 => string '2016/01/21' (length=10)
3 => string '2016/01/28' (length=10)
回答by Anttila
$dates = array();
$dates[] = strtotime($start);
for($i = 0; $i <= 12; $i++){
$dates[] = strtotime('+1 week', $dates[$i]);
}
foreach($dates as $date){ echo date("d.m.Y", $date); }
I had similar issue and courses can start on any day. This script picks starting day and collect next days every week until the wanted amount (12 in this case).
我有类似的问题，课程可以在任何一天开始。此脚本选择开始日期并每周收集下几天，直到所需金额（在本例中为 12）。
回答by saurabh
This is code for fetching the weekday of "$startdate" and counting the number of weekdays between two dates.
这是用于获取“$startdate”的工作日并计算两个日期之间的工作日数的代码。
`$startdate` = '2015-03-01';
`$endate` = '2015-03-31';
`$recurringDay` = date('N', strtotime($startdate)); // recurring Day from date i.e monday = 1, Tuesday = 2 ...etc
$begin = new DateTime(`$startdate`);
$end = new DateTime(date('Y-m-d',strtotime('+1 day', strtotime($endate))));
while($begin format('Y-m-d');
$day[] = $begin->format('N');
$begin->modify('+1 day');
}
$c=0; // counter starts
foreach($day as $key=>$dt) {
if ($dt==`$recurringDay`) // compare it
{
$k[] = $key;
$c++;
}
}
`$nofDays` = $c; // number of mondays , tuesday
foreach($k as $pp) {
//adding session code
`$recurringDatetime[]` = $period[$pp]; // recurring dates
}
print_r(`$recurringDatetime`); // array of dates of monday, tuesday ..etc
回答by Andreas
Convert $startDate and $endDate before that to timestamps:
将之前的 $startDate 和 $endDate 转换为时间戳：
foreach ($date = $startDate; $date <= $endDate; $date += 60 * 60 * 24) {
if (strftime('%w', $date) == 1) {
$mondays[] = strftime('%A %Y-%m-%d', $date);
}
}
回答by Lakmal Bodhinayaka
simply you can add as,
只需添加为，
$date_from = "2007-02-05";
$date_from = strtotime($date_from);
$date_to="2007-02-20";
$date_to = strtotime($date_to);
for ($i=$date_from; $i<=$date_to; $i+=86400) {
$day = date("Y-m-d", $i);
$unixTimestamp = strtotime($day);
$dayOfWeek = date("l", $unixTimestamp);
if ($dayOfWeek == "Monday") {
echo $day ."is a". $dayOfWeek;
}
}//end for
回答by Yunier López Martínez
I made some changes to response https://stackoverflow.com/a/37300272/6871295
我对响应进行了一些更改https://stackoverflow.com/a/37300272/6871295
Then I can get the days between dates for any day and return format.
然后我可以获得任何一天的日期和返回格式之间的天数。
public function getWeekDayInRange($weekday, $dateFromString, $dateToString, $format = 'Y-m-d')
{
$dateFrom = new \DateTime($dateFromString);
$dateTo = new \DateTime($dateToString);
$dates = [];
if ($dateFrom > $dateTo) {
return $dates;
}
if (date('N', strtotime($weekday)) != $dateFrom->format('N')) {
$dateFrom->modify("next $weekday");
}
while ($dateFrom <= $dateTo) {
$dates[] = $dateFrom->format($format);
$dateFrom->modify('+1 week');
}
return $dates;
}
