十六进制转储文件的pythonic方法
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/25005505/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
pythonic way to hex dump files
提问by peluzza
my question is simple:
我的问题很简单：
Is there any way to code in a pythonic way that bash command?
有没有办法以 bash 命令的pythonic方式进行编码？
hexdump -e '2/1 "%02x"' file.dat
Obviously, without using os, popen, or any shortcut ;)
显然，不使用 os、popen 或任何快捷方式；)
EDIT: although I've not explicitly specified, it would be great if the code was functional in Python3.x
编辑：虽然我没有明确指定，但如果代码在 Python3.x 中运行，那就太好了
Thanks!
谢谢！
采纳答案by abarnert
If you only care about Python 2.x, line.encode('hex')will encode a chunk of binary data into hex. So:
如果您只关心 Python 2.x，line.encode('hex')会将一大块二进制数据编码为十六进制。所以：
with open('file.dat', 'rb') as f:
for chunk in iter(lambda: f.read(32), b''):
print chunk.encode('hex')
(IIRC, hexdumpby default prints 32 pairs of hex per line; if not, just change that 32to 16or whatever it is…)
（IIRC，hexdump默认情况下每行打印 32 对十六进制；如果没有，只需将其更改32为16或其他任何内容......）
If the two-argument iterlooks baffling, click the help link; it's not too complicated once you get the idea.
如果两个参数iter看起来莫名其妙，请单击帮助链接；一旦你有了想法，它并不太复杂。
If you care about Python 3.x, encodeonly works for codecs that convert Unicode strings to bytes; any codecs that convert the other way around (or any other combination), you have to use codecs.encodeto do it explicitly:
如果您关心 Python 3.x，则encode仅适用于将 Unicode 字符串转换为字节的编解码器；任何以相反方式（或任何其他组合）转换的编解码器，您都必须使用codecs.encode明确地进行转换：
with open('file.dat', 'rb') as f:
for chunk in iter(lambda: f.read(32), b''):
print(codecs.encode(chunk, 'hex'))
Or it may be better to use hexlify:
或者最好使用hexlify：
with open('file.dat', 'rb') as f:
for chunk in iter(lambda: f.read(32), b''):
print(binascii.hexlify(chunk))
If you want to do something besides print them out, rather than read the whole file into memory, you probably want to make an iterator. You could just put this in a function and change that printto a yield, and that function returns exactly the iterator you want. Or use a genexpr or mapcall:
如果你想在打印之外做一些事情，而不是将整个文件读入内存，你可能想要制作一个迭代器。您可以将它放在一个函数中并将其更改print为 a yield，该函数将准确返回您想要的迭代器。或者使用geneexpr或map调用：
with open('file.dat', 'rb') as f:
chunks = iter(lambda: f.read(32), b'')
hexlines = map(binascii.hexlify, chunks)
回答by kay - SE is evil
Simply read()the whole file and encode('hex'). What could be more pythonic?
只需read()整个文件和encode('hex'). 什么可以更pythonic？
with open('file.dat', 'rb') as f:
hex_content = f.read().encode('hex')
回答by Raymond Hettinger
The standard library is your friend. Try binascii.hexlify().
标准库是你的朋友。尝试binascii.hexlify()。
