bash 按上次编辑日期列出文件
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List files by last edited date
提问by Marty
I have a directory: /home/user/
我有一个目录： /home/user/
How can I list every file in this directory (including those in sub directories) and order them by the date that they were last modified?
如何列出此目录中的每个文件（包括子目录中的文件）并按上次修改日期对其进行排序？
回答by mipadi
You can use:
您可以使用：
ls -Rt
where -Rmeans recursive(include subdirectories) and -tmeans "sort by last modification date".
其中-R表示递归（包括子目录）并-t表示“按上次修改日期排序”。
To see a list of files sorted by date modified, use:
要查看按修改日期排序的文件列表，请使用：
ls -l -Rt
An alias can also be created to achieve this:
还可以创建别名来实现此目的：
alias lt='ls -lht'
lt
Where -hgives a more readable output.
哪里-h给出了更具可读性的输出。
回答by Paused until further notice.
If you'd like a master list in which all the files are sorted togetherby modification date, showing the directory they're in, but not grouped by directory, you can use this:
如果您想要一个主列表，其中所有文件按修改日期排序在一起，显示它们所在的目录，但不按 directory 分组，您可以使用：
find . -type f -printf "%-.22T+ %M %n %-8u %-8g %8s %Tx %.8TX %p\n" | sort | cut -f 2- -d ' '
The result looks a lot like ls -l:
结果看起来很像ls -l：
-rw-r--r-- 1 root root 3892 08/11/2009 11:03:36 /usr/share/man/man1/xmllint.1.gz -rw-r--r-- 1 root root 22946 08/13/2009 11:59:20 /usr/share/man/man1/curl.1.gz -rw-r--r-- 1 root root 728 08/17/2009 12:06:33 /usr/share/man/man1/thunderbird.1.gz -rw-r--r-- 1 root root 873 08/18/2009 10:52:47 /usr/share/man/man1/libgnutls-config.1.gz -rw-r--r-- 1 root root 2552 08/19/2009 02:00:34 /usr/share/man/man3/Purple.3pm.gz -rw-r--r-- 1 root root 9546 08/19/2009 02:02:00 /usr/share/man/man1/pidgin.1.gz -rw-r--r-- 1 root root 2201 08/19/2009 02:02:46 /usr/share/man/man3/Pidgin.3pm.gz -rw-r--r-- 1 root root 926 08/19/2009 02:03:05 /usr/share/man/man1/purple-remote.1.gz -rw-r--r-- 1 root root 18052 08/19/2009 04:11:47 /usr/share/man/man1/mono.1.gz -rw-r--r-- 1 root root 1845 08/19/2009 04:11:47 /usr/share/man/man5/mono-config.5.gz
Mac OS X
Mac OS X
For those of you using Mac OS X, option -printfis not available on BSD find (you will get this error: find: -printf: unknown primary or operator). Fortunately you can Install GNU find through Homebrew(there should be an option to Finkand Macportsas well):
对于那些使用 Mac OS X 的人，选项-printf在 BSD find 上不可用（你会得到这个错误：）find: -printf: unknown primary or operator。幸运的是，您可以通过Homebrew安装 GNU find （Fink和Macports也应该有一个选项）：
brew install findutils
After install it the GNU find should be available to you as gfind. So, all you need to do is change the line above to:
安装后，GNU find 应该可以作为gfind. 因此，您需要做的就是将上面的行更改为：
gfind . -type f -printf "%-.22T+ %M %n %-8u %-8g %8s %Tx %.8TX %p\n" | sort | cut -f 2- -d ' '
回答by Mussa Charles
MAC OSX 2019
MAC OSX 2019
If you don't care about what time it was created but you want your list sorted then use this command
如果您不关心它的创建时间，但希望对列表进行排序，请使用此命令
==> ls -t
==> ls -t
If you want to order and see date and user info use this command
如果您想订购并查看日期和用户信息，请使用此命令
===> ls -lt
===> ls -lt
回答by Ulysse BN
For zshusers, you could also use glob qualifiers(also documented on man zshexpn):
对于zsh用户，您还可以使用glob 限定符（也记录在man zshexpn）：
echo *(om)
Where ostands for sort order, upand mstands for last modification time.
其中o代表排序顺序，增长和m代表最后修改时间。
This can be useful when used in a for loop or another command:
这在 for 循环或其他命令中使用时很有用：
for file in *(^om); do
[ -e "$file" ] || continue
# do something with file orderer from least recently modified to last modified
done
Or chained with another glob qualifier:
或者与另一个 glob 限定符链接：
last_modified_file=(*(om[1]))
