循环遍历python正则表达式匹配

Looping through python regex matches

提问by da5id

This has to be easier than what I am running into. My problem is turning a string that looks like this:

这必须比我遇到的更容易。我的问题是转动一个看起来像这样的字符串：

ABC12DEF3G56HIJ7

into

进入

12 * ABC
3  * DEF
56 * G
7  * HIJ

And I can't, for the life of me, design a correct set of loops using REGEX matching. The crux of the issue is that the code has to be completely general because I cannot assume how long the [A-Z]fragments will be, nor how long the [0-9]fragments will be.

而且我一生都无法使用 REGEX 匹配设计一组正确的循环。问题的关键是代码必须是完全通用的，因为我不能假设这些[A-Z]片段会有多长，也不能假设这些片段会有多长[0-9]。

Thank you for any assistance!

感谢您的任何帮助！

采纳答案by Ray Toal

Python's re.findallshould work for you.

Pythonre.findall应该适合你。

Live demo

现场演示

import re

s = "ABC12DEF3G56HIJ7"
pattern = re.compile(r'([A-Z]+)([0-9]+)')

for (letters, numbers) in re.findall(pattern, s):
    print(numbers, '*', letters)

回答by Mithril

It is better to use re.finditerif you dataset is large:

如果数据集很大，最好使用re.finditer：

import re

s = "ABC12DEF3G56HIJ7"
pattern = re.compile(r'([A-Z]+)([0-9]+)')

for m in re.finditer(pattern, s):
    print m.group(2), '*', m.group(1)