C语言 警告：传递“__builtin___strncpy_chk”参数 1 中的指针目标的符号不同
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warning: pointer targets in passing argument 1 of '__builtin___strncpy_chk' differ in signedness
提问by Angus
I am getting a warning for the below code.
我收到以下代码的警告。
//someother class
#define EVENT_ID_DESCRIPTION_LEN 64
struct FILE_DESCRIPTIONS
{
uint32_t uFileID;
uint32_t uDescriptionLen;
int8_t szDescription[FILE_ID_DESCRIPTION_LEN];
};
//defined inside a function of someother class
int8_t chTemp[EVENT_ID_DESCRIPTION_LEN + 1];
strncpy(chTemp,pMsg->st.aDescriptions[nIndex].szDescription,EVENT_ID_DESCRIPTION_LEN);
warning: pointer targets in passing argument 1 of '_builtin__strncpy_chk' differ in signedness
警告：传递“_内置__strncpy_chk” 的参数 1 中的指针目标的符号不同
The value from which i'm storing from is also uint8_t and that gets stored onto is also uint8_t.what might be the cause of this warning. Thanks in advance.
我从中存储的值也是 uint8_t 并且存储到的值也是 uint8_t。这可能是此警告的原因。提前致谢。
回答by karlphillip
Actually, your code is defining int8_t(signed int) and not uint8_t(unsigned int) as you think. Did you spotted it?
实际上，您的代码定义了int8_t（有符号整数）而不是您认为的uint8_t（无符号整数）。你发现了吗？
You have to change your variable to:
您必须将变量更改为：
uint8_t chTemp[EVENT_ID_DESCRIPTION_LEN + 1];
回答by Kerrek SB
Remember that in C, the three types char, unsigned charand signed charare all distinct, and strncpyexpects a char. If your int8_tis defined as signed char, you have conflicting types. Best to use an actual char, non?
请记住，在 C 中，三种类型char,unsigned char和signed char都是不同的，并且strncpy期望一个char. 如果您int8_t的定义为signed char，则您的类型存在冲突。最好使用实际的char，非？
回答by Deepak Danduprolu
Can't you use memcpyinstead?
你不能用memcpy吗？
memcpy(chTemp, pMsg->st.aDescriptions[nIndex].szDescription, EVENT_ID_DESCRIPTION_LEN);
