python 正则表达式拆分换行符的连续性
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Regex to split on successions of newline characters
提问by Humphrey Bogart
I'm trying to split a string on newline characters (catering for Windows, OS X, and Unix text file newline characters). If there are any succession of these, I want to split on that too and not include anyin the result.
我正在尝试在换行符上拆分字符串（适用于 Windows、OS X 和 Unix 文本文件换行符）。如果有任何连续的这些，我也想对其进行拆分，而不在结果中包含任何内容。
So, for when splitting the following:
因此，在拆分以下内容时：
"Foo\r\n\r\nDouble Windows\r\rDouble OS X\n\nDouble Unix\r\nWindows\rOS X\nUnix"
The result would be:
结果将是：
['Foo', 'Double Windows', 'Double OS X', 'Double Unix', 'Windows', 'OS X', 'Unix']
What regex should I use?
我应该使用什么正则表达式？
回答by magcius
If there are no spaces at the starts or ends of the lines, you can use line.split()with no arguments. It will remove doubles.
.
If not, you can use [a for a a.split("\r\n") if a].
如果行的开头或结尾没有空格，则可以line.split()不带参数使用。它将删除双打。. 如果没有，您可以使用[a for a a.split("\r\n") if a].
EDIT: the strtype also has a method called "splitlines".
编辑：该str类型还有一个称为“分割线”的方法。
"Foo\r\n\r\nDouble Windows\r\rDouble OS X\n\nDouble Unix\r\nWindows\rOS X\nUnix".splitlines()
"Foo\r\n\r\nDouble Windows\r\rDouble OS X\n\nDouble Unix\r\nWindows\rOS X\nUnix".splitlines()
回答by Alex Martelli
The simplest pattern for this purpose is r'[\r\n]+'which you can pronounce as "one or more carriage-return or newline characters".
用于此目的的最简单模式是r'[\r\n]+'您可以将其发音为“一个或多个回车符或换行符”。
回答by Ignacio Vazquez-Abrams
re.split(r'[\n\r]+', line)
回答by ghostdog74
>>> s="Foo\r\n\r\nDouble Windows\r\rDouble OS X\n\nDouble Unix\r\nWindows\rOS X\nUnix"
>>> import re
>>> re.split("[\r\n]+",s)
['Foo', 'Double Windows', 'Double OS X', 'Double Unix', 'Windows', 'OS X', 'Unix']
回答by jlettvin
Paying attention to the greediness rules for patterns:
注意模式的贪婪规则：
pattern = re.compile(r'(\r\n){2,}|(\n\r){2,}|(\r){2,}|(\n){2,}')
paragraphs = pattern.split(text)
