Android Spinner ：当所选项目保持不变时不调用 onItemSelected

Spinner : onItemSelected not called when selected item remains the same

提问by elgui

I have a OnItemSelectedListenerfor my Spinner, but it is not called when the selected item is the same as the previous one. Apparently the OnClickListeneris not an option for a Spinner. I need to catch everytime a user click on an item. Any idea?

我有一个OnItemSelectedListenerfor my Spinner，但是当所选项目与前一个项目相同时不会调用它。显然OnClickListener不是Spinner. 每次用户点击一个项目时，我都需要捕捉。任何的想法？

Maybe the fact that this Spinneris inside the ActionBardisturbs normal behavior?

也许这Spinner是内部ActionBar干扰正常行为的事实？

@Override
public void onCreateOptionsMenu(Menu menu, MenuInflater inflater) {
    inflater.inflate(R.menu.tracklist_menu, menu);
    Spinner spinner = (Spinner) menu.findItem(R.id.option_ordering_spinner)
            .getActionView();
    spinner.setAdapter(mSpinnerAdapter);
    spinner.setSelection(PrefsHelper.getOrderingSpinnerPos(prefs));
    spinner.setOnItemSelectedListener(new OnItemSelectedListener() {

        @Override
        public void onItemSelected(AdapterView<?> parent, View view,
                int position, long id) {
            String str = "selected";
            System.out.println(str);
            if (optionMenuInitialized) {

                switch (position) {
                case 0:
                    // rdm
                    getActivity()
                            .sendBroadcast(
                                    new Intent(
                                            MyIntentAction.DO_RESHUFFLE_PLAYLIST));
                    smp.setCurrentTracklistCursorPos(-1);
                    trackAdapter.notifyDataSetChanged();
                    break;
                case 1:
                    // artist
                    getActivity()
                            .sendBroadcast(
                                    new Intent(
                                            MyIntentAction.DO_ORDER_PLAYLIST_BY_ARTIST));
                    smp.setCurrentTracklistCursorPos(-1);
                    trackAdapter.notifyDataSetChanged();
                    break;
                case 2:
                    // folder
                    getActivity()
                            .sendBroadcast(
                                    new Intent(
                                            MyIntentAction.DO_ORDER_PLAYLIST_BY_FOLDER));
                    smp.setCurrentTracklistCursorPos(-1);
                    trackAdapter.notifyDataSetChanged();
                    break;
                }
                PrefsHelper.setOrderingSpinnerPos(prefEditor, position);
                prefEditor.commit();
            }
            optionMenuInitialized = true;
        }

        @Override
        public void onNothingSelected(AdapterView<?> parent) {
        }
    });
}

回答by elgui

Ok, I finally found a solution, by creating my own class extending Spinner :

好的，我终于找到了一个解决方案，通过创建我自己的扩展 Spinner 的类：

public class MySpinner extends Spinner {
OnItemSelectedListener listener;

public MySpinner(Context context, AttributeSet attrs) {
    super(context, attrs);
}

@Override
public void setSelection(int position) {
    super.setSelection(position);
    if (listener != null)
        listener.onItemSelected(null, null, position, 0);
}

public void setOnItemSelectedEvenIfUnchangedListener(
        OnItemSelectedListener listener) {
    this.listener = listener;
}
}

回答by Eric Leong Zhia Choong

I found out this work instead of the one provided

我发现了这项工作而不是提供的工作

/** Spinner extension that calls onItemSelected even when the selection is the same as its previous value */
public class NDSpinner extends Spinner {

  public NDSpinner(Context context)
  { super(context); }

  public NDSpinner(Context context, AttributeSet attrs)
  { super(context, attrs); }

  public NDSpinner(Context context, AttributeSet attrs, int defStyle)
  { super(context, attrs, defStyle); }

  @Override public void
  setSelection(int position, boolean animate)
  {
    boolean sameSelected = position == getSelectedItemPosition();
    super.setSelection(position, animate);
    if (sameSelected) {
      // Spinner does not call the OnItemSelectedListener if the same item is selected, so do it manually now
      getOnItemSelectedListener().onItemSelected(this, getSelectedView(), position, getSelectedItemId());
    }
  }

  @Override public void
  setSelection(int position)
  {
    boolean sameSelected = position == getSelectedItemPosition();
    super.setSelection(position);
    if (sameSelected) {
      // Spinner does not call the OnItemSelectedListener if the same item is selected, so do it manually now
      getOnItemSelectedListener().onItemSelected(this, getSelectedView(), position, getSelectedItemId());
    }
  }
}

回答by Alecs

Here a little better implementation:

这里有一个更好的实现：

public class SpinnerPlus extends Spinner {
    AdapterView.OnItemSelectedListener listener;

    public SpinnerPlus(Context context, AttributeSet attrs) {
        super(context, attrs);
    }

    @Override
    public void setSelection(int position) {
        super.setSelection(position);
        if (listener != null)
            listener.onItemSelected(this, getSelectedView(), position, 0);
    }

    public void setOnItemSelectedEvenIfUnchangedListener(
            AdapterView.OnItemSelectedListener listener) {
        this.listener = listener;
    }
}

回答by Ramiro G.M.

To make your spinner change despite the value of the last index selected just use a:

尽管选择了最后一个索引的值，但要使您的微调器更改，只需使用：

spinner.setSelection(0); 

before your other selection is called

在调用您的其他选择之前

spinner.setSelection(number); 

this way, the spinner will trigger two times the OnItemSelectedevent. Just make sure the second time it does whatever you need.

这样，微调器将触发两次OnItemSelected事件。只要确保第二次它做你需要的任何事情。

回答by soshial

Rewrote the common solution but with:

重写了通用解决方案，但使用：

1. androidx in mind
2. extended from AppCompatSpinner
3. use built-in OnItemSelectedListenerlistener instead of creating own one
4. added initial listener call hack

1. androidx 记住了
2. 延伸自 AppCompatSpinner
3. 使用内置OnItemSelectedListener监听器而不是创建自己的监听器
4. 添加了初始侦听器调用 hack

Here:

这里：

import android.content.Context;

import androidx.annotation.Nullable;
import androidx.appcompat.widget.AppCompatSpinner;


public class FixedSpinner extends AppCompatSpinner {
    // add other constructors that you need
    public FixedSpinner(Context context, int mode) {
        super(context, mode);
    }

    private void processSelection(int position) {
        boolean sameSelected = position == getSelectedItemPosition();
        final OnItemSelectedListener listener = getOnItemSelectedListener();
        if (sameSelected && listener != null) {
            // Spinner does not call the OnItemSelectedListener if the same item is selected, so do it manually now
            listener.onItemSelected(this, getSelectedView(), position, getSelectedItemId());
        }
    }

    @Override
    public void setSelection(int position) {
        processSelection(position);
        super.setSelection(position);
    }

    @Override
    public void setSelection(int position, boolean animate) {
        processSelection(position);
        super.setSelection(position, animate);
    }

    @Override
    public void setOnItemSelectedListener(@Nullable OnItemSelectedListener listener) {
        // This hack fixes bug, when immediately after initialization, listener is called
        // To make this fix work, first add data, only then set listener
        // Having done this, you may refresh adapter data as many times as you want
        setSelection(0, false);
        super.setOnItemSelectedListener(listener);
    }
}

回答by Martin Edlman

If it's still actual, correct call of the callback should be

如果它仍然是实际的，则回调的正确调用应该是

@Override
public void setSelection(int position) {
    super.setSelection(position);
    if(listener != null)
        listener.onItemSelected(this, getChildAt(position), position, 0);
}

Martin

马丁

回答by Nishant Shah

Simplest solution :

最简单的解决方案：

spinner.performItemClick(view,position,id)

spinner.performItemClick(view,position,id)

回答by Marek Kondracki

I had same problem, I solved it by setting onItemSelectedListener every time adapter changes items.

我遇到了同样的问题，我通过在每次适配器更改项目时设置 onItemSelectedListener 来解决它。

回答by Abhishek Vishwakarma

i found a simple solution

我找到了一个简单的解决方案

just call setAdapter again in place of notifyDataSetChanged for the second spinner

只需再次调用 setAdapter 代替第二个微调器的 notifyDataSetChanged