php 取消设置元素后重新设置数组键
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Rebase array keys after unsetting elements
提问by TuK
I have an array:
我有一个数组：
$array = array(1,2,3,4,5);
If I were to dump the contents of the array they would look like this:
如果我要转储数组的内容，它们将如下所示：
array(5) {
[0] => int(1)
[1] => int(2)
[2] => int(3)
[3] => int(4)
[4] => int(5)
}
When I loop through and unset certain keys, the index gets all Hymaned up.
当我循环并取消设置某些键时，索引会全部被提升。
foreach($array as $i => $info)
{
if($info == 1 || $info == 2)
{
unset($array[$i]);
}
}
Subsequently, if I did another dump now it would look like:
随后，如果我现在再做一次转储，它看起来像：
array(3) {
[2] => int(3)
[3] => int(4)
[4] => int(5)
}
Is there a proper way to reset the array so it's elements are Zero based again ??
是否有正确的方法来重置数组，使其元素再次基于零？？
array(3) {
[0] => int(3)
[1] => int(4)
[2] => int(5)
}
回答by Naftali aka Neal
回答by Web_Developer
Got another interesting method:
还有一个有趣的方法：
$array = array('a', 'b', 'c', 'd');
unset($array[2]);
$array = array_merge($array);
Now the $array keys are reset.
现在 $array 键被重置。
回答by Demian Brecht
Use array_splicerather than unset:
使用array_splice而不是unset：
$array = array(1,2,3,4,5);
foreach($array as $i => $info)
{
if($info == 1 || $info == 2)
{
array_splice($array, $i, 1);
}
}
print_r($array);
回答by SpYk3HH
Just an additive.
只是一种添加剂。
I know this is old, but I wanted to add a solution I don't see that I came up with myself. Found this question while on hunt of a different solution and just figured, "Well, while I'm here."
我知道这很旧，但我想添加一个我自己没有想到的解决方案。在寻找不同的解决方案时发现了这个问题，只是想，“好吧，当我在这里的时候。”
First of all, Neal's answer is good and great to use after you run your loop, however, I'd prefer do all work at once. Of course, in my specific case I had to do morework than this simple example here, but the method still applies. I saw where a couple others suggested foreachloops, however, this still leaves you with after workdue to the nature of the beast. Normally I suggest simpler things like foreach, however, in this case, it's best to remember good old fashioned for looplogic. Simply use i! To maintain appropriate index, just subtract from iafter each removal of an Array item.
首先，Neal的答案很好，在您运行循环后非常适合使用，但是，我更喜欢一次完成所有工作。当然，在我的特定情况下，我必须做比这里的这个简单示例更多的工作，但该方法仍然适用。我看到其他几个人建议foreach循环的地方，但是，由于野兽的性质，这仍然让你在下班后留下来。通常我建议使用更简单的东西foreach，但是，在这种情况下，最好记住好的老式for loop逻辑。只需使用i！要保持适当的索引，只需i在每次删除 Array 项后减去。
Here's my simple, workingexample:
这是我的简单工作示例：
$array = array(1,2,3,4,5);
for ($i = 0; $i < count($array); $i++) {
if($array[$i] == 1 || $array[$i] == 2) {
array_splice($array, $i, 1);
$i--;
}
}
Will output:
将输出：
array(3) {
[0]=> int(3)
[1]=> int(4)
[2]=> int(5)
}
This can have many simple implementations. For example, my exact case required holding of latest item in array based on multidimensional values. I'll show you what I mean:
这可以有许多简单的实现。例如，我的确切情况需要根据多维值在数组中保存最新项目。我会告诉你我的意思：
$files = array(
array(
'name' => 'example.zip',
'size' => '100000000',
'type' => 'application/x-zip-compressed',
'url' => '28188b90db990f5c5f75eb960a643b96/example.zip',
'deleteUrl' => 'server/php/?file=example.zip',
'deleteType' => 'DELETE'
),
array(
'name' => 'example.zip',
'size' => '10726556',
'type' => 'application/x-zip-compressed',
'url' => '28188b90db990f5c5f75eb960a643b96/example.zip',
'deleteUrl' => 'server/php/?file=example.zip',
'deleteType' => 'DELETE'
),
array(
'name' => 'example.zip',
'size' => '110726556',
'type' => 'application/x-zip-compressed',
'deleteUrl' => 'server/php/?file=example.zip',
'deleteType' => 'DELETE'
),
array(
'name' => 'example2.zip',
'size' => '12356556',
'type' => 'application/x-zip-compressed',
'url' => '28188b90db990f5c5f75eb960a643b96/example2.zip',
'deleteUrl' => 'server/php/?file=example2.zip',
'deleteType' => 'DELETE'
)
);
for ($i = 0; $i < count($files); $i++) {
if ($i > 0) {
if (is_array($files[$i-1])) {
if (!key_exists('name', array_diff($files[$i], $files[$i-1]))) {
if (!key_exists('url', $files[$i]) && key_exists('url', $files[$i-1])) $files[$i]['url'] = $files[$i-1]['url'];
$i--;
array_splice($files, $i, 1);
}
}
}
}
Will output:
将输出：
array(1) {
[0]=> array(6) {
["name"]=> string(11) "example.zip"
["size"]=> string(9) "110726556"
["type"]=> string(28) "application/x-zip-compressed"
["deleteUrl"]=> string(28) "server/php/?file=example.zip"
["deleteType"]=> string(6) "DELETE"
["url"]=> string(44) "28188b90db990f5c5f75eb960a643b96/example.zip"
}
[1]=> array(6) {
["name"]=> string(11) "example2.zip"
["size"]=> string(9) "12356556"
["type"]=> string(28) "application/x-zip-compressed"
["deleteUrl"]=> string(28) "server/php/?file=example2.zip"
["deleteType"]=> string(6) "DELETE"
["url"]=> string(45) "28188b90db990f5c5f75eb960a643b96/example2.zip"
}
}
As you see, I manipulate $i before the splice as I'm seeking to remove the previous, rather than the present item.
如您所见，我在拼接之前操作 $i ，因为我试图删除前一项，而不是当前项。
回答by upful
Or you can make your own function that passes the array by reference.
或者，您可以创建自己的函数，通过引用传递数组。
function array_unset($unsets, &$array) {
foreach ($array as $key => $value) {
foreach ($unsets as $unset) {
if ($value == $unset) {
unset($array[$key]);
break;
}
}
}
$array = array_values($array);
}
So then all you have to do is...
那么你所要做的就是......
$unsets = array(1,2);
array_unset($unsets, $array);
... and now your $arrayis without the values you placed in $unsetsand the keys are reset
......现在你$array没有你放置的值$unsets并且键被重置
回答by K-Gun
Late answer but, after PHP 5.3 could be so;
迟到的答案但是，在 PHP 5.3 之后可能是这样；
$array = array(1, 2, 3, 4, 5);
$array = array_values(array_filter($array, function($v) {
return !($v == 1 || $v == 2);
}));
print_r($array);
回答by Atta Ur Rehman
100% working for me ! After unset elements in array you can use this for re-indexing the array
100% 为我工作！在数组中取消设置元素后，您可以使用它来重新索引数组
$result=array_combine(range(1, count($your_array)), array_values($your_array));
回答by Rockin4Life33
I use $arr = array_merge($arr);to rebase an array. Simple and straightforward.
我用来 $arr = array_merge($arr);重新定义一个数组。简单明了。
回答by John K
In my situation, I needed to retain unique keys with the array values, so I just used a second array:
在我的情况下，我需要使用数组值保留唯一键，所以我只使用了第二个数组：
$arr1 = array("alpha"=>"bravo","charlie"=>"delta","echo"=>"foxtrot");
unset($arr1);
$arr2 = array();
foreach($arr1 as $key=>$value) $arr2[$key] = $value;
$arr1 = $arr2
unset($arr2);
