使用基本访问身份验证从 Python 读取 https url
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Read https url from Python with basic access authentication
提问by Etam
How do you open https url in Python?
你如何在 Python 中打开 https url？
import urllib2
url = "https://user:[email protected]/path/
f = urllib2.urlopen(url)
print f.read()
gives:
给出：
httplib.InvalidURL: nonnumeric port: '[email protected]'
回答by John Giotta
This has never failed me
这从来没有让我失望
import urllib2, base64
username = 'foo'
password = 'bar'
auth_encoded = base64.encodestring('%s:%s' % (username, password))[:-1]
req = urllib2.Request('https://somewebsite.com')
req.add_header('Authorization', 'Basic %s' % auth_encoded)
try:
response = urllib2.urlopen(req)
except urllib2.HTTPError, http_e:
# etc...
pass
回答by S.Lott
Please read about the urllib2 password manager and the basic authentication handler as well as the digest authentication handler.
请阅读 urllib2 密码管理器和基本身份验证处理程序以及摘要身份验证处理程序。
http://docs.python.org/library/urllib2.html#abstractbasicauthhandler-objects
http://docs.python.org/library/urllib2.html#abstractbasicauthhandler-objects
http://docs.python.org/library/urllib2.html#httpdigestauthhandler-objects
http://docs.python.org/library/urllib2.html#httpdigestauthhandler-objects
Your urllib2 script must actually provide enough information to do HTTP authentication. Usernames, Passwords, Domains, etc.
您的 urllib2 脚本实际上必须提供足够的信息来进行 HTTP 身份验证。用户名、密码、域名等。
回答by Dave Webb
If you want to pass username and password information to urllib2you'll need to use an HTTPBasicAuthHandler.
如果要将用户名和密码信息传递给urllib2您，则需要使用HTTPBasicAuthHandler.
回答by Johannes Charra
You cannot pass credentials to urllib2.openlike that. In your case, useris interpreted as the domain name, while [email protected]is interpreted as the port number.
你不能urllib2.open像那样传递凭据。在您的情况下，user被解释为域名，而[email protected]被解释为端口号。
