Python matplotlib：更改当前轴实例（即 gca()）
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matplotlib: change the current axis instance (i.e., gca())
提问by Liang
I use a trick to draw a colorbar whose height matches the master axes. The code is like
我使用一个技巧来绘制一个高度与主轴匹配的颜色条。代码就像
import matplotlib.pyplot as plt
from mpl_toolkits.axes_grid1 import make_axes_locatable
import numpy as np
ax = plt.subplot(111)
im = ax.imshow(np.arange(100).reshape((10,10)))
# create an axes on the right side of ax. The width of cax will be 5%
# of ax and the padding between cax and ax will be fixed at 0.05 inch.
divider = make_axes_locatable(ax)
cax = divider.append_axes("right", size="5%", pad=0.05)
plt.colorbar(im, cax=cax)
This trick works good. However, since a new axis is appended, the current instance of the figure becomes cax - the appended axis. As a result, if one performs operations like
这个技巧效果很好。但是，由于附加了新轴，图形的当前实例变为 cax - 附加轴。因此，如果执行类似的操作
plt.text(0,0,'whatever')
the text will be drawn on cax instead of ax - the axis to which im belongs.
文本将绘制在 cax 而不是 ax - im 所属的轴上。
Meanwhile, gcf().axes shows both axes.
同时， gcf().axes 显示两个轴。
My question is: How to make the current axis instance (returned by gca()) the original axis to which im belongs.
我的问题是：如何使当前轴实例（由 gca() 返回）成为 im 所属的原始轴。
采纳答案by Joe Kington
Use plt.sca(ax)to set the current axes, where axis the Axesobject you'd like to become active.
使用plt.sca(ax)设置当前轴，其中ax是Axes你想成为活动对象。
