如何通过 NodeJS 子进程运行命令？
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How to run commands via NodeJS child process?
提问by Tower
I am trying to run commands on Windows via NodeJS child processes:
我正在尝试通过 NodeJS 子进程在 Windows 上运行命令：
var terminal = require('child_process').spawn('cmd');
terminal.stdout.on('data', function (data) {
console.log('stdout: ' + data);
});
terminal.stderr.on('data', function (data) {
console.log('stderr: ' + data);
});
terminal.on('exit', function (code) {
console.log('child process exited with code ' + code);
});
setTimeout(function() {
terminal.stdin.write('echo %PATH%');
}, 2000);
When it calls ti.stdin.write, it writes it to the stdindescriptor, but how do I trigger cmdto react at this point? How do I send the "enter" key signal that you do when you are actually typing in command prompt? Currently I get no response from cmd.
当它调用时ti.stdin.write，它会将它写入stdin描述符，但是此时我如何触发cmd以做出反应？当您实际输入命令提示符时，如何发送您执行的“输入”键信号？目前我没有收到来自cmd.
回答by toabi
Sending a newline \nwill exectue the command. .end()will exit the shell.
发送换行符\n将执行命令。.end()将退出外壳。
I modified the example to work with bash as I'm on osx.
我修改了示例以使用 bash，因为我在 osx 上。
var terminal = require('child_process').spawn('bash');
terminal.stdout.on('data', function (data) {
console.log('stdout: ' + data);
});
terminal.on('exit', function (code) {
console.log('child process exited with code ' + code);
});
setTimeout(function() {
console.log('Sending stdin to terminal');
terminal.stdin.write('echo "Hello $USER. Your machine runs since:"\n');
terminal.stdin.write('uptime\n');
console.log('Ending terminal session');
terminal.stdin.end();
}, 1000);
The output will be:
输出将是：
Sending stdin to terminal
Ending terminal session
stdout: Hello root. Your machine runs since:
stdout: 9:47 up 50 mins, 2 users, load averages: 1.75 1.58 1.42
child process exited with code 0
回答by Raivo Laanemets
You just have to send line end (\n) with the command:
您只需使用以下命令发送行尾 (\n)：
setTimeout(function() {
terminal.stdin.write('echo %PATH%\n');
}, 2000);
回答by cuixiping
You can use child_process exec method. here is an example:
您可以使用 child_process exec 方法。这是一个例子：
var exec = require('child_process').exec,
child;
child = exec('echo %PATH%',
function (error, stdout, stderr) {
if(stdout!==''){
console.log('---------stdout: ---------\n' + stdout);
}
if(stderr!==''){
console.log('---------stderr: ---------\n' + stderr);
}
if (error !== null) {
console.log('---------exec error: ---------\n[' + error+']');
}
});
回答by kgilpin
Make sure you stdin.end()at some point or the child process won't exit.
确保您stdin.end()在某个时候或子进程不会退出。
