nodejs 相当于这个 .htaccess

nodejs equivalent of this .htaccess

提问by Glats

Is it possible to build a code like this in node.js?

是否可以在中构建这样的代码node.js？

<IfModule mod_rewrite.c>
???? RewriteEngine on

???? RewriteCond% {REQUEST_URI}! / (View) / [NC]
???? RewriteCond% {REQUEST_FILENAME}!-F
???? RewriteRule ^ (. *) $ Index.html [L, QSA]

</IfModule>

url display a route is not "view" and also the file does not exist then write index.html.

url 显示路由不是“查看”并且文件不存在然后写入index.html.

using something like expressor connect

使用类似express或connect

UPDATE: I need a regular expression for !/(view)/in route for expressin node.js.

更新：我需要一个正则表达式!/(view)/的路线express中node.js。

采纳答案by Glats

The final structure is:

最终的结构是：

var express = require('express'), url = require('url');

var app = express();
app.use(function(req, res, next) {
    console.log('%s %s', req.method, req.url);
    next();
});
app.configure(function() {
    var pub_dir = __dirname + '/public';
    app.set('port', process.env.PORT || 8080);
    app.engine('.html', require('ejs').__express);
    app.set('views', __dirname + '/views');
    app.set('view engine', 'html');
    app.use(express.bodyParser());
    app.use(express.methodOverride());
    app.use(express.cookieParser());
    app.use(express.static(pub_dir));
    app.use(app.router);
});
app.get('/*', function(req, res) {
    if (req.xhr) {
        var pathname = url.parse(req.url).pathname;
        res.sendfile('index.html', {root: __dirname + '/public' + pathname});
    } else {
        res.render('index');
    }
});

app.listen(app.get('port'));

Thanks everyone. PD: Render html with module ejs

谢谢大家。PD：使用模块 ejs 渲染 html

回答by sbstjn

Have you tried:

你有没有尝试过：

1. Serve statics
2. Catch /view URL

3. Catch everything else

   app.configure(function(){
     app.use(express.static(__dirname+'/public')); // Catch static files
     app.use(app.routes);
   });
   
   // Catch /view and do whatever you like
   app.all('/view', function(req, res) {
   
   });
   
   // Catch everything else and redirect to /index.html
   // Of course you could send the file's content with fs.readFile to avoid
   // using redirects
   app.all('*', function(req, res) { 
     res.redirect('/index.html'); 
   });
   

1. 服务静态
2. 捕获/查看 URL

3. 抓住一切

   app.configure(function(){
     app.use(express.static(__dirname+'/public')); // Catch static files
     app.use(app.routes);
   });
   
   // Catch /view and do whatever you like
   app.all('/view', function(req, res) {
   
   });
   
   // Catch everything else and redirect to /index.html
   // Of course you could send the file's content with fs.readFile to avoid
   // using redirects
   app.all('*', function(req, res) { 
     res.redirect('/index.html'); 
   });
   

OR

或者

1. Serve statics

2. Check if URL is /view

   app.configure(function(){
     app.use(express.static(__dirname+'/public')); // Catch static files
     app.use(function(req, res, next) {
       if (req.url == '/view') {
         next();
       } else {
         res.redirect('/index.html');
       }
     });
   });
   

1. 服务静态

2. 检查 URL 是否为 /view

   app.configure(function(){
     app.use(express.static(__dirname+'/public')); // Catch static files
     app.use(function(req, res, next) {
       if (req.url == '/view') {
         next();
       } else {
         res.redirect('/index.html');
       }
     });
   });
   

OR

或者

1. Catch statics as usual

2. Catch NOT /view

   app.configure(function(){
     app.use(express.static(__dirname+'/public')); // Catch static files
     app.use(app.routes);
   });
   
   app.get(/^(?!\/view$).*$/, function(req, res) {
     res.redirect('/index.html');
   });
   

1. 像往常一样捕捉静态

2. 赶不上/查看

   app.configure(function(){
     app.use(express.static(__dirname+'/public')); // Catch static files
     app.use(app.routes);
   });
   
   app.get(/^(?!\/view$).*$/, function(req, res) {
     res.redirect('/index.html');
   });
   

回答by Bojoer

I would recommend using the express Middleware urlrewrite.

我建议使用快速中间件 urlrewrite。

If you don't handle rewrites on a reverse proxy for example and if using express and want regex support for flexibility use: https://www.npmjs.com/package/express-urlrewrite

例如，如果您不处理反向代理上的重写，并且如果使用 express 并希望使用正则表达式支持灵活性，请使用：https: //www.npmjs.com/package/express-urlrewrite