java 使用 Joda，如何确定给定日期是否在时间 x 和比 x 早 3 小时的时间之间？
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Using Joda, How do I determine if a given date is between time x and a time 3 hours earlier than x?
提问by Alex B
What is the simplest way to use Joda time and get something like the following behavior:
使用 Joda 时间并获得类似以下行为的最简单方法是什么：
public boolean check( DateTime checkTime )
{
DateTime someTime = new DateTime(); //set to "now" for sake of example
return checkTime.isBefore( someTime ) && checkTime.notMoreThanThreeHoursBefore( someTime );
}
So if someTimeis set to 15:00 and checkTimeis set to 12:15 it should return true.
因此，如果someTime设置为 15:00 并checkTime设置为 12:15，它应该返回 true。
If someTimeis set to 15:00 and checkTimeis set to 11:45 it should return false because checkTimeis more than 3 hours before someTime.
如果someTime设置为 15:00 并checkTime设置为 11:45 它应该返回 false 因为checkTime是 3 个多小时之前someTime。
If someTimeis set to 15:00 and checkTimeis set to 15:15 it should return false because checkTimeis after someTime.
如果someTime设置为 15:00 并checkTime设置为 15:15 它应该返回 false 因为checkTime是 after someTime。
回答by Alex B
After some playing around, I found this which reads nicely:
经过一番玩耍后，我发现这个读起来很好：
return new Interval( someTime.minusHours( 3 ), someTime ).contains( checkTime );
回答by Jon Skeet
Easy:
简单：
DateTime someTime = new DateTime();
DateTime earliest = someTime.minusHours(3);
if (earliest.compareTo(checkTime) <= 0 && checkTime.compareTo(someTime) < 0)
I've used compareToas there's no isBeforeOrEqualor isAfterOrEqual- but you can use compareTofor any relation.
我用过compareTo因为没有isBeforeOrEqual或isAfterOrEqual- 但你可以compareTo用于任何关系。
I suspect it was just minusHoursthat you were after though :)
我怀疑这只是minusHours你在追求:)
