C语言 内置函数“malloc”的不兼容隐式声明
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Incompatible implicit declaration of built-in function ‘malloc’
提问by SGE
I'm getting this error:
我收到此错误：
warning: incompatible implicit declaration of built-in function ‘malloc'
警告：内置函数“malloc”的隐式声明不兼容
I am trying to do this:
我正在尝试这样做：
fileinfo_list* tempList = malloc(sizeof(fileinfo_list));
Just for the reference the struct used at hand is:
仅供参考，手头使用的结构是：
typedef struct {
fileinfo** filedata;
size_t nFiles;
size_t size;
size_t fileblock;
} fileinfo_list;
I don't see anything wrong with what I've done. I'm just creating a tempListwith the size of 1 x fileinfo_list.
我认为我所做的没有任何问题。我只是创建一个tempList大小为 1 x fileinfo_list。
回答by cnicutar
You likely forgot to include <stdlib.h>.
您可能忘记包含<stdlib.h>.
回答by Omri Barel
You need to #include <stdlib.h>. Otherwise it's defined as int malloc()which is incompatible with the built-in type void *malloc(size_t).
你需要#include <stdlib.h>。否则它被定义为int malloc()与内置类型不兼容void *malloc(size_t)。
回答by Antti
You're missing #include <stdlib.h>.
你不见了#include <stdlib.h>。
回答by santosh sahu
The stdlib.h file contains the header information or prototype of the malloc, calloc, realloc and free functions.
stdlib.h 文件包含 malloc、calloc、realloc 和 free 函数的头信息或原型。
So to avoid this warning in ANSI C, you should include the stdlib header file.
因此，为了避免 ANSI C 中出现此警告，您应该包含 stdlib 头文件。
回答by user3828152
The only solution for such warnings is to include stdlib.h in the program.
此类警告的唯一解决方案是在程序中包含 stdlib.h。
