php Yii - 如何将模型数据检索到布局页面中？
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Yii - how to retrieve model data into a layout page?
提问by MEM
I wish to list some Categories name on my layout main.php page. Since the layout doesn't have any associated controller or model, I wish to create a static method like this on Category model:
我希望在我的布局 main.php 页面上列出一些类别名称。由于布局没有任何关联的控制器或模型，我希望在类别模型上创建一个像这样的静态方法：
public static function getHeaderModels()
{
// get all models here
return $models;
}
and then in the main layout
然后在主布局中
<?php
$models = Category::getHeaderModels();
foreach($models as $model)
{
// ....
}
?>
My question is a very basic one: How can I retrieve those category names from the model ?
我的问题是一个非常基本的问题： 如何从模型中检索这些类别名称？
Here is the full model:
这是完整的模型：
class Category extends CActiveRecord {
public static function model($className=__CLASS__) {
return parent::model($className);
}
public function tableName() {
return 'category';
}
public function rules() {
return array(
array('parent_id', 'numerical', 'integerOnly' => true),
array('name', 'length', 'max' => 255),
array('id, parent_id, name', 'safe', 'on' => 'search'),
);
}
public function relations() {
return array(
'users' => array(self::MANY_MANY, 'User', 'categories(category_id, user_id)'),
);
}
public function scopes()
{
return array(
'toplevel'=>array(
'condition' => 'parent_id IS NULL'
),
);
}
public function attributeLabels() {
$id = Yii::t('trans', 'ID');
$parentId = Yii::t('trans', 'Parent');
$name = Yii::t('trans', 'Name');
return array(
'id' => $id,
'parent_id' => $parentId,
'name' => $name,
);
}
public function search() {
$criteria = new CDbCriteria;
$criteria->compare('id', $this->id);
$criteria->compare('parent_id', $this->parent_id);
$criteria->compare('name', $this->name, true);
return new CActiveDataProvider(get_class($this), array(
'criteria' => $criteria,
));
}
public static function getHeaderModels() {
//what sintax should I use to retrieve the models here ?
? ? return $models;
}
回答by aslingga
May be this answer can help you. First you must create a Widget so you can use it more effectively.
也许这个答案可以帮助你。首先，您必须创建一个 Widget，以便您可以更有效地使用它。
First Create a new widget. Let say the name is CategoryWidget. Put this widget under components directory protected/components.
首先创建一个新的小部件。假设名称是CategoryWidget. 将此小部件放在 components 目录下protected/components。
class CategoryWidget extends CWidget {
public function run() {
$models = Category::model()->findAll();
$this->render('category', array(
'models'=>$models
));
}
}
Then create a view for this widget. The file name is category.php.
Put it under protected/components/views
然后为这个小部件创建一个视图。文件名为 category.php。把它放在下面protected/components/views
category.php
类别.php
<?php if($models != null): ?>
<ul>
<?php foreach($models as $model): ?>
<li><?php echo $model->name; ?></li>
<?php endforeach; ?>
</ul>
<?php endif; ?>
Then call this widget from your main layout.
然后从您的主布局调用这个小部件。
main.php
主文件
// your code ...
<?php $this->widget('CategoryWidget') ?>
...
回答by tonino.j
If I'm not mistaken, you can also pass any variable available in a view, on to the layout. You just do it from the view that has your variable. This is the catch: you need to declare the variable which will receive your value, in the controller, like this:
如果我没记错的话，您还可以将视图中可用的任何变量传递给布局。您只需从具有您的变量的视图中进行操作即可。这就是问题所在：您需要在控制器中声明将接收您的值的变量，如下所示：
<?php
class MyController extends Controller
{
public $myvariable;
After this, you will assign your model or whatever to this public variable inside your view, like this:
在此之后，您将您的模型或任何内容分配给您视图中的此公共变量，如下所示：
$this->myvariable = $modeldata;
After you have assigned your model data to controller's public attribute, you can easily display it inside your layout e.g.
将模型数据分配给控制器的公共属性后，您可以轻松地在布局中显示它，例如
echo $this->myvariable;
Yii already does this by assigning menu items to column2 sidebar menu, from view, like this:
Yii 已经通过将菜单项分配给 column2 侧边栏菜单来做到这一点，从视图来看，如下所示：
$this->menu=array(
array('label'=>'List Item', 'url'=>array('index')),
array('label'=>'Manage Item', 'url'=>array('admin')),
);
You can see it in all create/update views that gii crud creates.
您可以在 gii crud 创建的所有创建/更新视图中看到它。
