在 Python 中创建列表对象类

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时间:2020-08-19 08:16:41  来源:igfitidea点击:

Create List Object Class in Python

pythonlistclassappend

提问by arnobpl

It is a basic question. I am trying the following code:

这是一个基本问题。我正在尝试以下代码:

class SMS_store:

def __init__(self):
    self=[]    #probably something is wrong here

def add_new_arrival(self,from_number,time_arrived,text_of_SMS):
    self.append([False,from_number,time_arrived,text_of_SMS])    #append list to self list
    self[len(self)-1]=tuple(self[len(self)-1])

def message_count(self):
    return len(self)

my_inbox=SMS_store()
my_inbox.add_new_arrival('01234','9:37 AM','How are you?')

But I get the following error:

但我收到以下错误:

>>> 
Traceback (most recent call last):
  File "C:\Users\Arnob\Desktop\New Text Document.py", line 15, in <module>
    my_inbox.add_new_arrival('01234','9:37 AM','How are you?')
  File "C:\Users\Arnob\Desktop\New Text Document.py", line 8, in add_new_arrival
    self.append([False,from_number,time_arrived,text_of_SMS])    #append list to self list
AttributeError: 'SMS_store' object has no attribute 'append'
>>>

What is wrong in my code?

我的代码有什么问题?

采纳答案by John La Rooy

You can subclass listlike this

你可以list像这样子类化

class SMS_store(list):

    def add_new_arrival(self, from_number, time_arrived, text_of_SMS):
        self.append((False, from_number, time_arrived, text_of_SMS))    #append tuple to self

    def message_count(self):
        return len(self)

Notice there is no need for __init__unless you wish to do something extra there.

请注意,__init__除非您想在那里做一些额外的事情,否则没有必要。

You don't need to append a list and then turn it into a tuple, you can create the tuple directly with ()instead of []

你不需要附加一个列表然后把它变成一个元组,你可以直接用()而不是创建元组[]

回答by TerryA

You need to still create a normal variable name, just put self.as a prefix:

您仍然需要创建一个普通的变量名,只需self.作为前缀:

self.mylist = []

To access it, you do something like:

要访问它,您可以执行以下操作:

self.mylist.append(n)

Or:

或者:

self.mylist[3] = 'hi'

You're actually overriding self. You don't want to do that.

你实际上是覆盖self. 你不想那样做。

回答by NPE

If you want to inherit from list, use the following:

如果要继承自list,请使用以下命令:

class SMS_store(list):
               ^^^^^^

and remove that assignment to selffrom the __init__method.

self__init__方法中删除该赋值。

That said, you might want to simply have a named attribute containing the list:

也就是说,您可能只想拥有一个包含列表的命名属性:

class SMS_store(object):

   def __init__(self):
      self.messages = []

   def add_new_arrival(self, from_number, time_arrived, text_of_SMS):
      self.messages.append((False,from_number,time_arrived,text_of_SMS))

   def message_count(self):
      return len(self.messages)

my_inbox = SMS_store()
my_inbox.add_new_arrival('01234','9:37 AM','How are you?')

As far as representing actual messages, this sounds like a good use case for namedtuple. It's just like a tuple, but allows access to fields by name. Here is a quick illustration:

就表示实际消息而言,这听起来像是namedtuple. 它就像一个元组,但允许按名称访问字段。这是一个快速说明:

import collections

SMS = collections.namedtuple('SMS', 'from_number time_arrived text_of_SMS')

sms = SMS(from_number='01234', time_arrived='9:37 AM', text_of_SMS='How are you?')
print sms.text_of_SMS