使用 Python 将数字转换为相应的字母
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Convert numbers into corresponding letter using Python
提问by user3556962
I was wondering if it is possible to convert numbers into their corresponding alphabetical value. So
我想知道是否可以将数字转换为其相应的字母值。所以
1 -> a
2 -> b
I was planning to make a program which lists all the alphabetical combinations possible for a length specified by a user.
我打算制作一个程序，列出用户指定长度的所有可能的字母组合。
See I know how to build the rest of the program except this! Any help would be wonderful.
看我知道如何构建程序的其余部分，除了这个！任何帮助都会很棒。
回答by vaultah
import string
for x, y in zip(range(1, 27), string.ascii_lowercase):
print(x, y)
or
或者
import string
for x, y in enumerate(string.ascii_lowercase, 1):
print(x, y)
or
或者
for x, y in ((x + 1, chr(ord('a') + x)) for x in range(26)):
print(x, y)
All of the solutions above output lowercase letters from English alphabet along with their position:
以上所有解决方案都输出英文字母中的小写字母及其位置：
1 a
...
26 z
You'd create a dictionary to access letters (values) by their position (keys) easily. For example:
您可以创建一个字典来轻松访问字母（值）的位置（键）。例如：
import string
d = dict(enumerate(string.ascii_lowercase, 1))
print(d[3]) # c
回答by Martijn Pieters
You can use chr()to turn numbers into characters, but you need to use a higher starting point as there are several other characters in the ASCII table first.
您可以使用chr()将数字转换为字符，但您需要使用更高的起点，因为 ASCII 表中还有其他几个字符。
Use ord('a') - 1as a starting point:
使用ord('a') - 1为出发点：
start = ord('a') - 1
a = chr(start + 1)
Demo:
演示：
>>> start = ord('a') - 1
>>> a = chr(start + 1)
>>> a
'a'
Another alternative is to use the string.ascii_lowercaseconstantas a sequence, but you need to start indexing from zero:
另一种方法是使用string.ascii_lowercase常数作为一个序列，但你需要从开始索引零：
import string
a = string.ascii_lowercase[0]
回答by running gherkin
If you just want to map between letters and numbers in your own way, Dictionaryis what you should look at.
如果您只想以自己的方式在字母和数字之间进行映射，那么您应该查看字典。
回答by wflynny
What about a dictionary?
字典呢？
>>> import string
>>> num2alpha = dict(zip(range(1, 27), string.ascii_lowercase))
>>> num2alpha[2]
b
>>> num2alpha[25]
y
But don't go over 26:
但不要超过26：
>>> num2alpha[27]
KeyError: 27
But if you are looking for all alphabetical combinations of a given length:
但是，如果您正在寻找给定长度的所有字母组合：
>>> import string
>>> from itertools import combinations_with_replacement as cwr
>>> alphabet = string.ascii_lowercase
>>> length = 2
>>> ["".join(comb) for comb in cwr(alphabet, length)]
['aa', 'ab', ..., 'zz']
回答by Hugh Bothwell
Here is a quick solution:
这是一个快速的解决方案：
# assumes Python 2.7
OFFSET = ord("a") - 1
def letter(num):
return chr(num + OFFSET)
def letters_sum_to(total):
for i in xrange(1, min(total, 27)):
for rem in letters_sum_to(total - i):
yield [letter(i)] + rem
if total <= 26:
yield [letter(total)]
def main():
for letters in letters_sum_to(8):
print("".join(letters))
if __name__=="__main__":
main()
which produces
产生
aaaaaaaa
aaaaaab
aaaaaba
aaaaac
aaaabaa
aaaabb
aaaaca
aaaad
aaabaaa
# etc
Note that the number of solutions totalling to N is 2**(N-1).
请注意，总计为 N 的解数为 2**(N-1)。
回答by khushbu
for i in range(0, 100):
mul = 1
n = i
if n >= 26:
n = n-26
mul = 2
print chr(65+n)*mul
回答by LinconFive
Big Letter:
大信：
chr(ord('@')+number)
1 -> A
1 -> A
2 -> B
2 -> 乙
...
...
Small Letter:
很小的字：
chr(ord('`')+number)
1 -> a
1 -> 一个
2 -> b
2 -> 乙
...
...
回答by ben
Try a dict and some recursion:
尝试一个 dict 和一些递归：
def Getletterfromindex(self, num):
#produces a string from numbers so
#1->a
#2->b
#26->z
#27->aa
#28->ab
#52->az
#53->ba
#54->bb
num2alphadict = dict(zip(range(1, 27), string.ascii_lowercase))
outval = ""
numloops = (num-1) //26
if numloops > 0:
outval = outval + self.Getletterfromindex(numloops)
remainder = num % 26
if remainder > 0:
outval = outval + num2alphadict[remainder]
else:
outval = outval + "z"
return outval
