如何在 bash curl 语句中包含“&”字符
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How to include an '&' character in a bash curl statement
提问by Chernoff
I'm trying to use curl in bash to download a webpage, but the &symbol in the URL isn't interpreted as a character as I would like. Any ideas on how I can convince bash that the symbol &is just a boring character and nothing special?
我正在尝试在 bash 中使用 curl 来下载网页，但&URL 中的符号没有像我希望的那样解释为字符。关于如何让 bash 相信该符号&只是一个无聊的角色而没有什么特别之处的任何想法？
采纳答案by Chernoff
Putting single quotes around the &symbol seems to work. That is, using a URL like http://www.example.com/page.asp?arg1=${i}'&'arg2=${j}with curl returns the requested webpage.
在&符号周围加上单引号似乎有效。也就是说，使用类似http://www.example.com/page.asp?arg1=${i}'&'arg2=${j}curl的 URL 会返回请求的网页。
回答by mjuarez
Putting the entire URL inside double quotes should take care of your problem.
将整个 URL 放在双引号内应该可以解决您的问题。
回答by Matt Clark
curl "http://www.example.com?m=method&args=1"
Are you using the & as a delimiter for a GET URL? Or is in a piece of data?
您是否使用 & 作为 GET URL 的分隔符？或者是在一段数据中？
If it is in data you must encode it to an HTML character, if not, surround with quotes.
如果它在数据中，您必须将其编码为 HTML 字符，如果不是，则用引号括起来。
The encoding for &should become %26in the URL.
编码&应该%26在 URL 中。
curl "http://www.example.com?m=this%26that
回答by noego
Instead of trying the escape "&" characters, you can specify http url parameters in POST requests with -d parameter as shown below:
您可以使用 -d 参数在 POST 请求中指定 http url 参数，而不是尝试转义“&”字符，如下所示：
curl -X POST http://www.example.com \
-d arg1=this \
-d arg2=that
If the request is a GET, then you should also add -G option, which tells curl to send the data with GET request.
如果请求是 GET，那么您还应该添加 -G 选项，它告诉 curl 使用 GET 请求发送数据。
curl -X GET -G http://www.example.com \
-d arg1=this \
-d arg2=that
回答by Seralto
You can use %26instead &.
The entity code will work fine.
您可以%26改用&. 实体代码将正常工作。
