bash 在bash中动态创建数组

Create array in bash dynamically

提问by Sadiel

I would like to create and fill an array dynamically but it doesn't work like this:

我想动态创建和填充数组，但它不能像这样工作：

i=0
while true; do
    read input
    field[$i]=$input
    ((i++))
    echo {$field[$i]}  
done

采纳答案by chepner

The assignment is fine; the lookup is wrong:

任务很好；查找错误：

echo "${field[$i]}"

回答by Mat

Try something like this:

尝试这样的事情：

#! /bin/bash
field=()
while read -r input ; do
    field+=("$input")
done
echo Num items: ${#field[@]}
echo Data: ${field[@]}

It stops reading when no more input is available (end of file, ^Din the keyboard), then prints the number of elements read and the whole array.

当没有更多输入可用时（文件末尾，^D在键盘中），它停止读取，然后打印读取的元素数和整个数组。

回答by ormaaj

i= field=()
while :; do
    read -r 'field[i++]'
done

Is one way. mapfileis another. Or any of these. However what you've posted is valid.

是一种方式。mapfile是另一个。或任何这些。但是，您发布的内容是有效的。