php 如何在symfony2中获取请求参数

How to get the request parameters in symfony2

提问by Abdul Hamid

I am very new to symfony. In other languages like java and others I can use request.getParameter('parmeter name')to get the value.

我对 symfony 很陌生。在其他语言（如 java 和其他语言）中，我可以使用它request.getParameter('parmeter name')来获取值。

Is there anything similar that we can do with symfony2.
I have seen some examples but none is working for me. Suppose I have a form field with the name username. In the form action I tried to use something like this:

我们可以用 symfony2 做类似的事情吗？
我看过一些例子，但没有一个对我有用。假设我有一个名为username的表单字段。在表单操作中，我尝试使用以下内容：

$request = $this->getRequest();
$username= $request->request->get('username'); 

I have also tried

我也试过

$username = $request->getParameter('username');

$username = $request->getParameter('username');

and

和

$username=$request->request->getParameter('username');

But none of the options is working.However following worked fine:

但是没有一个选项有效。但是以下工作正常：

foreach($request->request->all() as $req){
    print_r($req['username']);
}

Where am I doing wrong in using getParameter()method. Any help will be appreciated.

我在使用getParameter()方法时做错了什么。任何帮助将不胜感激。

回答by Cerad

The naming is not all that intuitive:

命名并不是那么直观：

use Symfony\Component\HttpFoundation\Request;

public function updateAction(Request $request)
{
    // $_GET parameters
    $request->query->get('name');

    // $_POST parameters
    $request->request->get('name');

回答by pkout

I do it even simpler:

我做的更简单：

use Symfony\Component\HttpFoundation\Request;

public function updateAction(Request $request)
{
    $foo = $request->get('foo');
    $bar = $request->get('bar');
}

Another option is to introduce your parameters into your action function definition:

另一种选择是将参数引入到动作函数定义中：

use Symfony\Component\HttpFoundation\Request;

public function updateAction(Request $request, $foo, $bar)
{
    echo $foo;
    echo $bar;
}

which, then assumes that you defined {foo} and {bar} as part of your URL pattern in your routing.yml file:

然后假设您在 routing.yml 文件中将 {foo} 和 {bar} 定义为 URL 模式的一部分：

acme_myurl:
    pattern:  /acme/news/{foo}/{bar}
    defaults: { _controller: AcmeBundle:Default:getnews }

回答by ScoRpion

You can Use The following code to get your form field values

您可以使用以下代码获取表单字段值

use Symfony\Component\HttpFoundation\Request;

public function updateAction(Request $request)
{
    // retrieve GET and POST variables respectively
    $request->query->get('foo');
    $request->request->get('bar', 'default value if bar does not exist');
}

Or You can also get all the form values as array by using

或者您也可以通过使用将所有表单值作为数组获取

$request->request->all()

回答by MartinW.

try

尝试

$request->request->get('acme_demobundle_usertype')['username']

inspect attribute name of your formular field

检查公式字段的属性名称

回答by Reinherd

Inside a controller:

在控制器内部：

$request = $this->getRequest();
$username = $request->get('username');

回答by luchaninov

Your options:

您的选择：

1. Simple:
   • $request->request->get('param')($_POST['param']) or
   • $request->query->get('param')($_GET['param'])
2. Good Symfony forms with all validation, value transormation and form rendering with errors and many other features:
   • http://symfony.com/doc/current/book/forms.html
   • http://symfony.com/doc/current/cookbook/form/index.html
3. Something in between (see example below)

1. 简单的：
   • $request->request->get('param')( $_POST['param']) 或
   • $request->query->get('param')( $_GET['param'])
2. 良好的 Symfony 表单，具有所有验证、值转换和带有错误的表单渲染以及许多其他功能：
   • http://symfony.com/doc/current/book/forms.html
   • http://symfony.com/doc/current/cookbook/form/index.html
3. 介于两者之间（见下面的例子）

<?php
/**
 * @Route("/customers", name="customers")
 *
 * @param Request $request
 * @return Response
 */
public function index(Request $request)
{
    $optionsResolver = new OptionsResolver();
    $optionsResolver->setDefaults([
        'email' => '',
        'phone' => '',
    ]);
    $filter = $optionsResolver->resolve($request->query->all());

    /** @var CustomerRepository $customerRepository */
    $customerRepository = $this->getDoctrine()->getRepository('AppBundle:Customer');

    /** @var Customer[] $customers */
    $customers = $customerRepository->findFilteredCustomers($filter);

    return $this->render(':customers:index.html.twig', [
        'customers' => $customers,
        'filter' => $filter,
    ]);
}

More about OptionsResolver- http://symfony.com/doc/current/components/options_resolver.html

更多关于OptionsResolver- http://symfony.com/doc/current/components/options_resolver.html

回答by Ashish Awasthi

As now $this->getRequest()method is deprecated you need to inject Requestobject into your controller action like this:

由于现在$this->getRequest()方法已被弃用，您需要Request像这样将对象注入到控制器操作中：

public function someAction(Request $request)

after that you can use one of the following.

之后，您可以使用以下方法之一。

If you want to fetch POST data from request use following:

如果您想从请求中获取 POST 数据，请使用以下内容：

$request->request->get('var_name');

but if you want to fetch GET data from request use this:

但如果你想从请求中获取 GET 数据，请使用：

$request->query->get('var_name');

回答by Yoander

You can do it this:

你可以这样做：

$clientName = $request->request->get('appbundle_client')['clientName'];

Sometimes, when the attributes are protected, you can not have access to get the value for the common method of access:

有时，当属性受到保护时，您无法获取常用访问方法的值：

(POST)

（邮政）

 $clientName = $request->request->get('clientName');

(GET)

（得到）

$clientName = $request->query->get('clientName');

(GENERIC)

（通用的）

$clientName = $request->get('clientName');

回答by Antonis Charalambous

Most of the cases like getting query string or form parameters are covered in answers above.

上面的答案涵盖了大多数情况，例如获取查询字符串或表单参数。

When working with raw data, like a raw JSON string in the body that you would like to give as an argument to json_decode(), the method Request::getContent()can be used.

处理原始数据时，例如您想作为参数提供给 的正文中的原始 JSON 字符串，可以使用json_decode()该方法Request::getContent()。

$content = $request->getContent();

Additional useful informations on HTTP requests in Symfony can be found on the HttpFoundationpackage's documentation.

可以在HttpFoundation包的文档中找到有关 Symfony 中 HTTP 请求的其他有用信息。

回答by Meet

use Symfony\Component\HttpFoundation\Request;

public function indexAction(Request $request, $id) {

    $post = $request->request->all();

    $request->request->get('username');

}

Thanks , you can also use above code

谢谢，你也可以使用上面的代码