如何使用值初始化 Scala 不可变哈希图？
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How to initialize a Scala immutable hashmap with values?
提问by Ivan
What's the syntax to set immutable hashmap contents on initialization?
在初始化时设置不可变哈希图内容的语法是什么？
For example, if I was willing to hardcode an array, I'd write:
例如，如果我愿意对数组进行硬编码，我会写：
val a = Array (0, 1, 2, 3)
val a = 数组 (0, 1, 2, 3)
What's the analogue for immutable hashmaps (say I want it to contain 0->1 and 2->3 pairs) (in Scala 2.8)?
不可变哈希图的类似物是什么（假设我希望它包含 0->1 和 2->3 对）（在 Scala 2.8 中）？
回答by Arjan Blokzijl
Do you mean something like this?
你的意思是这样的吗？
scala> val m = collection.immutable.HashMap(0 -> 1, 2 -> 3)
m: scala.collection.immutable.HashMap[Int,Int] = Map((0,1), (2,3))
scala> m.get(0)
res0: Option[Int] = Some(1)
scala> m.get(2)
res1: Option[Int] = Some(3)
scala> m.get(1)
res2: Option[Int] = None
回答by samthebest
To create from a collection (remember NOT to have a newkeyword)
从集合创建（记住不要有new关键字）
val result: HashMap[Int, Int] = HashMap(myCollection: _*)
