如何在python中以数学方式减去两个列表？
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How to mathematically subtract two lists in python?
提问by Gareth Bale
I know subtraction of lists is not supported in python, however there are some ways to omit the common elements between two lists. But what I want to do is subtraction of each element in one list individually with the corresponding element in another list and return the result as an output list. How can I do this?
我知道 python 不支持列表的减法，但是有一些方法可以省略两个列表之间的公共元素。但是我想要做的是将一个列表中的每个元素分别与另一个列表中的相应元素相减，并将结果作为输出列表返回。我怎样才能做到这一点？
A = [3, 4, 6, 7]
B = [1, 3, 6, 3]
print A - B #Should print [2, 1, 0, 4]
采纳答案by Thanakron Tandavas
>>> A = [3, 4, 6, 7]
>>> B = [1, 3, 6, 3]
>>> map(operator.sub, A, B)
[2, 1, 0, 4]
As @SethMMortonmentioned below, in Python 3, you need this instead
正如下面提到的@SethMMorton，在 Python 3 中，你需要这个
>>> A = [3, 4, 6, 7]
>>> B = [1, 3, 6, 3]
>>> list(map(operator.sub, A, B))
[2, 1, 0, 4]
Because, mapin Python returns an iterator instead.
因为，Python 中的map返回一个迭代器。
回答by Gareth Bale
You can use zipand a list comprehension:
>>> A = [3, 4, 6, 7]
>>> B = [1, 3, 6, 3]
>>> zip(A, B) # Just to demonstrate
[(3, 1), (4, 3), (6, 6), (7, 3)]
>>> [x - y for x, y in zip(A, B)]
[2, 1, 0, 4]
>>>
回答by Lucas S.
Try something like
尝试类似的东西
def substract_lists(a, b):
for i, val in enumerate(a):
val = val - b[i]
return a
