Python请求库异常处理
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/24237185/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Python requests library Exception handling
提问by Frankline
I am creating a download service using the python requests library (See here) to download data from another server. The problem is that sometimes I get a 503 errorand I need to display an appropriate message. See sample code below:
我正在使用 python requests 库（请参阅此处）创建下载服务以从另一台服务器下载数据。问题是有时我会得到一个503 error，我需要显示一个适当的消息。请参阅下面的示例代码：
import requests
s = requests.Session()
response = s.get('http://mycustomserver.org/download')
I can check from response.status_codeand get the status code = 200.
But how do I try/catchfor a specific error, in this case, I want to be able to detect 503 errorand handle them appropriately.
我可以从检查response.status_code并获得status code = 200。但是我如何try/catch针对特定错误，在这种情况下，我希望能够503 error适当地检测和处理它们。
How do I do that?
我怎么做？
采纳答案by Martin Konecny
Why not do
为什么不做
class MyException(Exception);
def __init__(self, error_code, error_msg):
self.error_code = error_code
self.error_msg = error_msg
import requests
s = requests.Session()
response = s.get('http://mycustomserver.org/download')
if response.status_code == 503:
raise MyException(503, "503 error code")
Edit:
编辑：
It seems that requests library will also raise an Exception for you using response.raise_for_status()
似乎请求库也会为您引发异常使用 response.raise_for_status()
>>> import requests
>>> requests.get('https://google.com/admin')
<Response [404]>
>>> response = requests.get('https://google.com/admin')
>>> response.raise_for_status()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/lib/python2.7/dist-packages/requests/models.py", line 638, in raise_for_status
raise http_error
requests.exceptions.HTTPError: 404 Client Error: Not Found
Edit2:
编辑2：
Wrap you raise_for_statuswith the following try/except
raise_for_status用以下内容包裹你try/except
try:
if response.status_code == 503:
response.raise_for_status()
except requests.exceptions.HTTPError as e:
if e.response.status_code == 503:
#handle your 503 specific error
回答by K DawG
You might as well do this:
你也可以这样做：
try:
s = requests.Session()
response = requests.get('http://mycustomserver.org/download')
if response.status_code == 503:
response.raise_for_status()
except requests.exceptions.HTTPError:
print "oops something unexpected happened!"
response.raise_for_status()raises a requests.exceptions.HTTPErrorand here we are only calling response.raise_for_status()if the status code is equal to 503
response.raise_for_status()引发 a requests.exceptions.HTTPError，这里我们只response.raise_for_status()在状态码等于 503 时调用
