如何将多个命令传递给 Git BASH
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How to Pass Multiple Commands to Git BASH
提问by dudeNumber4
New to Git. Running it on windows. When I run this command in a .sh file (from a BASH shell), it works:
Git 新手。在 Windows 上运行它。当我在 .sh 文件（来自 BASH shell）中运行此命令时，它可以工作：
cd /c/SomeDir && git commit -a -m "commit comment"
cd /c/SomeDir && git commit -a -m "提交评论"
I want to do that with a variable comment, so I want to call: C:\Program Files\Git\usr\bin\bash.exe and pass the above command (2 commands chained) as the parameter (with a different comment each time).
我想用一个变量注释来做到这一点，所以我想调用： C:\Program Files\Git\usr\bin\bash.exe 并将上述命令（链接的 2 个命令）作为参数（每个都有不同的注释）时间）。
It doesn't work; looking for ideas...
它不起作用；寻找想法...
Clarification:I'm using a utility to run commands, but basically, this is all I want to call:
Executable:
C:\Program Files\Git\usr\bin\bash.exe
Parameters (if test.sh has everything it needs but the comment):
bash /c/somewhere/test.sh "my comment"
澄清：我正在使用一个实用程序来运行命令，但基本上，这就是我想要调用的全部：
Executable:
C:\Program Files\Git\usr\bin\bash.exe
参数（如果 test.sh 拥有它需要的一切但评论）：
bash /c/somewhere/test.sh“我的评论”
Alternatively, the Parameters could simply be:
cd /c/MyRepoDir && git commit -a -m "my comment"
或者，参数可以简单地为：
cd /c/MyRepoDir && git commit -a -m "my comment"
Further:Even after creating a .sh script, calling bash, and running that script, I still get an error, "Paths with -a does not make sense." Then, even after doing what's recommended here(same commands), I STILL get the same error.
进一步：即使在创建 .sh 脚本、调用 bash 并运行该脚本之后，我仍然收到错误消息，“带有 -a 的路径没有意义。” 然后，即使在执行此处推荐的操作（相同的命令）之后，我仍然会遇到相同的错误。
回答by Calvin Taylor
try putting $1 in to reference the first parameter
尝试将 $1 放入引用第一个参数
cd /c/SomeDir && git commit -a -m ""
so myScript.sh contains your line, then
所以 myScript.sh 包含你的行，然后
bash myScript.sh "this is my commit message"
an alternative to this approach from using cd is pushd and popd
使用 cd 的这种方法的替代方法是 pushd 和 popd
#!/bin/bash
pushd mygitdir
git commit -a -m ""
popd
