使用 bash 脚本读取文件
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Read a file using a bash script
提问by Leonardo
I need to read a file using a "Do/While" loop.
How can I read the contents as a string?
我需要使用“Do/While”循环读取文件。
如何将内容作为字符串读取？
Here's my code:
这是我的代码：
cat directory/scripts/tv2dbarray.txt | while read line
do
echo "a line: $line"
done
Error:
错误：
test.sh: line 4: syntax error near unexpected token `done'
test.sh: line 4: `done'
回答by Adam Liss
There's no reason to use cathere -- it adds no functionality and spawns an unnecessary process.
没有理由在cat这里使用——它不添加任何功能并产生一个不必要的过程。
while IFS= read -r line; do
echo "a line: $line"
done < file
To read the contents of a file into a variable, use
要将文件的内容读入变量，请使用
foo=$(<file)
(note that this trims trailing newlines).
（请注意，这会修剪尾随的换行符）。
回答by Erik
cat file | while read line
do
echo "a line: $line"
done
EDIT:
编辑：
To get file contents into a var use:
要将文件内容放入 var 使用：
foo="`cat file`"
回答by prudviraj
This should work:
这应该有效：
file=path/of/file/location/filename.txt
while IFS= read -r varname; do
printf '%s\n' "$varname"
done < "$file"
回答by pedram shabani
try it
尝试一下
while read p
do
echo $p
done < directory/scripts/tv2dbarray.txt
