bash 如何从目录中递归查找所有文件扩展名？
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How to find all file extensions recursively from a directory?
提问by Matthew
What command, or collection of commands, can I use to return all file extensions in a directory (including sub-directories)?
我可以使用什么命令或命令集合来返回目录（包括子目录）中的所有文件扩展名？
Right now, I'm using different combinations of lsand grep, but I can't find any scalable solution.
现在，我使用的不同组合ls和grep，但我无法找到任何可扩展解决方案。
回答by thkala
How about this:
这个怎么样：
find . -type f -name '*.*' | sed 's|.*\.||' | sort -u
回答by marcosdsanchez
find . -type f | sed 's|.*\.||' | sort -u
Also works on mac.
也适用于 mac。
回答by mindon
list all extensions and their counts of current and all sub-directories
列出所有扩展名及其当前和所有子目录的计数
ls -1R | sed 's/[^\.]*//' | sed 's/.*\.//' | sort | uniq -c
回答by kurumi
if you are using Bash 4+
如果您使用的是 Bash 4+
shopt -s globstar
for file in **/*.*
do
echo "${file##*.}
done
Ruby(1.9+)
红宝石（1.9+）
ruby -e 'Dir["**/*.*"].each{|x|puts x.split(".")[-1]}' | sort -u
回答by tooly
Yet another solution using find (that should even sort file extensions with embedded newlines correctly):
另一个使用 find 的解决方案（甚至应该正确地对带有嵌入换行符的文件扩展名进行排序）：
# [^.]: exclude dotfiles
find . -type f -name "[^.]*.*" -exec bash -c '
printf "%sfind * | awk -F . {'print '} | sort -u
0" "${@##*.}"
' argv0 '{}' + |
sort -uz |
tr 'ls -1 | sed 's/.*\.//' | sort -u
' '\n'
回答by ackuser
Boooom another:
嘘另一个：
##代码##回答by TimeDelta
Update: You are correct Matthew. Based on your comment, here is an updated version:
更新：你是对的，马修。根据您的评论，这是一个更新版本：
ls -R1 | egrep -C 0 "[^\.]+\.[^\./:]+$" | sed 's/.*\.//' | sort -u
ls -R1 | egrep -C 0 "[^\.]+\.[^\./:]+$" | sed 's/.*\.//' | sort -u
回答by Mehcs85
I was just quickly trying this as I was searching Google for a good answer. I am more Regex inclined than Bash, but this also works for subdirectories. I don't think includes files without extensions either:
我只是在快速尝试这个，因为我在谷歌搜索一个好的答案。我比 Bash 更倾向于 Regex，但这也适用于子目录。我也不认为包含没有扩展名的文件：
ls -R | egrep '(\.\w+)$' -o | sort | uniq -c | sort -r
ls -R | egrep '(\.\w+)$' -o | sort | uniq -c | sort -r
