bash 使用 xmllint 命令行的模式
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pattern using xmllint command-line
提问by iamauser
]$ xmllint --version
xmllint: using libxml version 20626
My xml file looks something like this:
我的 xml 文件看起来像这样：
<projects>
<architecture name="ARCH1">
<project label="StringA1" type="StringB1" state="StringC1"/>
......
</architecture>
<architecture name="ARCH2">
<project label="StringA2" type="StringB2" state="StringC2"/>
......
</architecture>
</projects>
For example, I would like to obtain the value StringB2given the condition name==ARCH2and state==StringC2. Is it possible using xmllintcommand line options, if yes, how ? Some examples will be beneficial.
例如，我想获得StringB2给定条件name==ARCH2和的值state==StringC2。是否可以使用xmllint命令行选项，如果是，如何？一些例子将是有益的。
I can extract these using sedor awkbut that may not be a good solution.
我可以使用sedor提取这些，awk但这可能不是一个好的解决方案。
回答by hek2mgl
Use:
用：
xmllint --xpath '//architecture[@name="ARCH2"]/project/@type'
or if you just want the string and only the string:
或者，如果您只想要字符串并且只想要字符串：
xmllint --xpath 'string(//architecture[@name="ARCH2"]/project/@type)'
While testing this statement I realized, that the ubuntu (12.04) version of xmllint (20708) terminates with a segfault when executing this command. I cloned the most recent version from https://git.gnome.org/browse/libxml2/refs/and compiled. Now the command above works.
在测试此语句时，我意识到 xmllint (20708) 的 ubuntu (12.04) 版本在执行此命令时以段错误终止。我从https://git.gnome.org/browse/libxml2/refs/克隆了最新版本并编译。现在上面的命令有效。
回答by Mark O'Connor
Try the following
尝试以下
xmllint --xpath 'string(///project[../@name="ARCH1" and @state="StringC1"]/@type)' data.xml
Version:
版本：
$ xmllint --version
xmllint: using libxml version 20900
compiled with: Threads Tree Output Push Reader Patterns Writer SAXv1 FTP HTTP DTDValid HTML Legacy C14N Catalog XPath XPointer XInclude Iconv ISO8859X Unicode Regexps Automata Expr Schemas Schematron Modules Debug Zlib Lzma
