将 Xml 转换为表 SQL Server
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Convert Xml to Table SQL Server
提问by Sanchitos
I wonder how can i read a xml data and transform it to a table in TSQL?
我想知道如何读取 xml 数据并将其转换为 TSQL 中的表?
For example:
例如:
<row>
<IdInvernadero>8</IdInvernadero>
<IdProducto>3</IdProducto>
<IdCaracteristica1>8</IdCaracteristica1>
<IdCaracteristica2>8</IdCaracteristica2>
<Cantidad>25</Cantidad>
<Folio>4568457</Folio>
</row>
<row>
<IdInvernadero>3</IdInvernadero>
<IdProducto>3</IdProducto>
<IdCaracteristica1>1</IdCaracteristica1>
<IdCaracteristica2>2</IdCaracteristica2>
<Cantidad>72</Cantidad>
<Folio>4568457</Folio>
</row>
To
到
8 3 8 8 25 4568457
3 3 1 2 72 4568457
回答by Sanchitos
This is the answer, hope it helps someone :)
这就是答案,希望它可以帮助某人:)
First there are two variations on how the xml can be written:
首先,关于如何编写 xml 有两种变体:
1
1
<row>
<IdInvernadero>8</IdInvernadero>
<IdProducto>3</IdProducto>
<IdCaracteristica1>8</IdCaracteristica1>
<IdCaracteristica2>8</IdCaracteristica2>
<Cantidad>25</Cantidad>
<Folio>4568457</Folio>
</row>
<row>
<IdInvernadero>3</IdInvernadero>
<IdProducto>3</IdProducto>
<IdCaracteristica1>1</IdCaracteristica1>
<IdCaracteristica2>2</IdCaracteristica2>
<Cantidad>72</Cantidad>
<Folio>4568457</Folio>
</row>
Answer:
回答:
SELECT
Tbl.Col.value('IdInvernadero[1]', 'smallint'),
Tbl.Col.value('IdProducto[1]', 'smallint'),
Tbl.Col.value('IdCaracteristica1[1]', 'smallint'),
Tbl.Col.value('IdCaracteristica2[1]', 'smallint'),
Tbl.Col.value('Cantidad[1]', 'int'),
Tbl.Col.value('Folio[1]', 'varchar(7)')
FROM @xml.nodes('//row') Tbl(Col)
2.
2.
<row IdInvernadero="8" IdProducto="3" IdCaracteristica1="8" IdCaracteristica2="8" Cantidad ="25" Folio="4568457" />
<row IdInvernadero="3" IdProducto="3" IdCaracteristica1="1" IdCaracteristica2="2" Cantidad ="72" Folio="4568457" />
Answer:
回答:
SELECT
Tbl.Col.value('@IdInvernadero', 'smallint'),
Tbl.Col.value('@IdProducto', 'smallint'),
Tbl.Col.value('@IdCaracteristica1', 'smallint'),
Tbl.Col.value('@IdCaracteristica2', 'smallint'),
Tbl.Col.value('@Cantidad', 'int'),
Tbl.Col.value('@Folio', 'varchar(7)')
FROM @xml.nodes('//row') Tbl(Col)
Taken from:
取自:
回答by xiaoyifang
The sp_xml_preparedocument
stored procedure will parse the XML and the OPENXML
rowset provider will show you a relational view of the XML data.
该sp_xml_preparedocument
存储过程将解析XML和OPENXML
行集提供程序会显示您的XML数据的关系视图。
For details and more examplescheck the OPENXML documentation.
有关详细信息和更多示例,请查看OPENXML 文档。
As for your question,
至于你的问题,
DECLARE @XML XML
SET @XML = '<rows><row>
<IdInvernadero>8</IdInvernadero>
<IdProducto>3</IdProducto>
<IdCaracteristica1>8</IdCaracteristica1>
<IdCaracteristica2>8</IdCaracteristica2>
<Cantidad>25</Cantidad>
<Folio>4568457</Folio>
</row>
<row>
<IdInvernadero>3</IdInvernadero>
<IdProducto>3</IdProducto>
<IdCaracteristica1>1</IdCaracteristica1>
<IdCaracteristica2>2</IdCaracteristica2>
<Cantidad>72</Cantidad>
<Folio>4568457</Folio>
</row></rows>'
DECLARE @handle INT
DECLARE @PrepareXmlStatus INT
EXEC @PrepareXmlStatus= sp_xml_preparedocument @handle OUTPUT, @XML
SELECT *
FROM OPENXML(@handle, '/rows/row', 2)
WITH (
IdInvernadero INT,
IdProducto INT,
IdCaracteristica1 INT,
IdCaracteristica2 INT,
Cantidad INT,
Folio INT
)
EXEC sp_xml_removedocument @handle