在 bash 中将来自不同文件的列压缩在一起
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zip columns from separate files together in bash
提问by nedned
I have two files which both contain a list of words. Is there an easy way to zip the contents of the files into one new file in bash, so that the resultant file would have two columns like this:
我有两个文件，它们都包含一个单词列表。有没有一种简单的方法可以将文件的内容压缩到 bash 中的一个新文件中，以便生成的文件有两列，如下所示：
file1_line1 file2_line1
file1_line2 file2_line2
file1_line3 file2_line3
file1_line4 file2_line4
回答by John Kugelman
NAME
姓名
paste-- merge corresponding or subsequent lines of files
paste-- 合并相应的或后续的文件行
SYNOPSIS
概要
paste [-s] [-d list] file ...
paste [-s] [-d list] file ...
DESCRIPTION
描述
The pasteutility concatenates the corresponding lines of the given input
files, replacing all but the last file's newline characters with a single
tab character, and writes the resulting lines to standard output.
该paste实用程序连接给定输入文件的相应行，用单个制表符替换除最后一个文件的换行符之外的所有行，并将结果行写入标准输出。
回答by Charles Ma
Paste will get you half way there, but you'll need sed to append the file name to the words
Paste 会让你成功，但你需要 sed 将文件名附加到单词中
Put this into a shell script and pass it the two files as arguments
将其放入 shell 脚本并将两个文件作为参数传递给它
#!/bin/sh
paste | sed -e "s/^\([^ ]\+\)\s\+\([^ ]\)/_ _/"
