python 将参数传递给 Django 中的动态表单
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passing arguments to a dynamic form in django
提问by user140736
I have a Dynamic Form in forms. How can I pass an argument from my view when I instantiate my form?
我在表单中有一个动态表单。当我实例化表单时，如何从我的视图中传递参数？
Something like:
就像是：
form = DynamicForm("some string argument I'm passing to my form")
This is the form I have:
这是我的表格：
class DynamicForm(Form):
def __init__(self, *args, **kwargs):
super(DynamicForm, self).__init__(*args, **kwargs)
for item in range(5):
self.fields['test_field_%d' % item] = CharField(max_length=255)
回答by gruszczy
Add it as keyword argument, say it's called my_arg. Make sure to pop()the keyword arg before calling super(), because the parent class's init method doesn't accept extra keyword arguments.
将其添加为关键字参数，假设它名为 my_arg。pop()在调用之前确保关键字 arg super()，因为父类的 init 方法不接受额外的关键字参数。
class DynamicForm(Form):
def __init__(self, *args, **kwargs):
my_arg = kwargs.pop('my_arg')
super(DynamicForm, self).__init__(*args, **kwargs)
for item in range(5):
self.fields['test_field_%d' % item] = CharField(max_length=255)
And when you create form it's like this:
当您创建表单时，它是这样的：
form = DynamicForm(..., my_arg='value')
回答by unlockme
You can also achieve this by overriding the get_form_kwargsof the FormMixin, available in class based views.
您还可以通过覆盖get_form_kwargs基于类的视图中可用的 FormMixin 的来实现这一点。
class CustomDynamicFormView(FormView): # inherit any view with formmixin...
form_class = DynamicForm
def get_form_kwargs(self):
kwargs = super(CustomDynamicFormView, self).get_form_kwargs()
kwargs['custom_variable'] = 'my custom variable'
return kwargs
Then in your form
然后在你的表格中
class DynamicForm(forms.Form):
def __init__(self, *args, *kwargs):
my_var = kwargs.pop('custom_variable')
# remove this b4 calling super otherwise it will complian
super(DynamicForm, self).__init__(*args, **kwargs)
# do what you want with my_var
